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Greeley [361]
3 years ago
7

A long string is pulled so that the tension in it increases by a factor of four. If the change in length is negligible, by what

factor does the wave speed change?
Physics
1 answer:
rusak2 [61]3 years ago
3 0

To solve this problem we will apply the concepts related to wave velocity as a function of the tension and linear mass density. This is

v = \sqrt{\frac{T}{\mu}}

Here

v = Wave speed

T = Tension

\mu = Linear mass density

From this proportion we can realize that the speed of the wave is directly proportional to the square of the tension

v \propto \sqrt{T}

Therefore, if there is an increase in tension of 4, the velocity will increase the square root of that proportion

v \propto \sqrt{4} = 2  

The factor that the wave speed change is 2.

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Question: Self-test 3.12 Calculate the change in G for ice at -10°C, with density 917 kg mº, when the pressure is increased from
Akimi4 [234]

The change in the Gibb's free energy per mole (G) is 1.96 J.

The given parameters:

  • Density of the ice, ρ = 917 kg/m³
  • Initial pressure, P₁ = 1.0 bar
  • Final pressure, P₂ = 2.0 bar
  • Temperature, T = - 10 C
  • Mass of water = 18 g

The change in the Gibb's free energy per mole (G) is calculated as follows;

\Delta G = V(P_2-P_1) \\\\

where;

V is the volume of the ice

Density = \frac{Mass}{Volume} \\\\Volume = \frac{Mass}{Density} \\\\Volume = \frac{18 \times 10^{-3} \ kg}{917 \ m^3} \\\\Volume = 1.96 \times 10^{-5} \ m^3\\\\Volume = 1.96 \times 10^{-5} \ m^3 \times \frac{1000 \ L}{m^3} \\\\Volume = 0.0196 \ L

Change in pressure;

P_2 - P_1 = 2.0 \ bar \ - \ 1.0 \ bar = 1.0 \ bar = 0.987 \ atm

The change in the Gibb's free energy per mole (G);

\Delta G= V(P_2-P_1)\\\\\Delta G = 0.0196\ L \times 0.987\ atm \\\\\Delta G = 0.0193 \ L.atm\\\\1 \ L.atm = 101.325 \ J\\\\\Delta G =  0.0193 \ L.atm \times \frac{101.325 \ J}{1 \ L.atm} \\\\\Delta G = 1.96 \ J

Thus, the change in the Gibb's free energy per mole (G) is 1.96 J.

Learn more about Gibb's free energy here: brainly.com/question/10012881

3 0
3 years ago
Compare the light gathering power of a 1 meter diameter telescope to that of the human eye ,which has a diameter of roughly 2.5
lesantik [10]

Answer:

The telescope can gather light 1600 times more than the human eyes can!

Explanation:

The light gathering ability of an optical element is directly proportional to its area of opening.

So, in comparing the light gathering abilities for two objects, it is just the ratio of their area of opening.

Let the diameter of the telescope be D = 1 m

And the diameter of the human eyes be d = 2.5 cm = 0.025 m

Light gathering ability of the telescope compared to the eyes = D² ÷ d²

= (D²/d²) = (1²/0.025²) = 1600 times.

The telescope can gather light 1600 times more than the human eyes can!

Hope this Helps!!!

7 0
3 years ago
If a car starts at rest and accelerates at 3.4 m/s^2 over a distance of 200 meters, how fast will it be travelling at the end?
CaHeK987 [17]

Answer:

36.9 m/s

Explanation:

From;

v^2 = u^2 + 2as

Where;

v = final velocity =?

a = acceleration = 3.4 m/s^2

u = initial velocity = 0 m/s

s = distance covered = 200 meters

v^2 = 0^2 + 2 * 3.4 * 200

v^2 = 1360

v = √1360

v = 36.9 m/s

8 0
2 years ago
A car moving at a steady 10 m/s on a level highway encounters a bump that has a circular cross-section with a radius of 30 m. Th
daser333 [38]

When you are driving over a circular bump, you can feel your body moving up a small distance in the seat. This make you feel like you weigh less that you really do. This is caused by the fact that net down force on you is equal to the centripetal force. If you go the following website, you will see a problem that is similar to this one. Go the problem called Sample Roller Coaster Problem.

At this website you can see that the normal force exerted by the seat of the car on a 60.0-kg passenger is equal to the difference of the passenger’s weight and the centripetal force.

Weight = 60 * 9.8 = 588 N

Fc = 60 * 10^2/30 = 200 N

Normal force = 388 N

Explanation:

8 0
3 years ago
At sea level, liquid water changes into water vapor ata temperature of 100°C. However, at high altitudes, it changes at a
Law Incorporation [45]
The answer is A: precipitation :)
3 0
3 years ago
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