Answer:
P.E = 4.398 Joules.
Explanation:
Given the following data;
Spring constant, k = 71.8N/m
Displacement, x = 0.35m
To find the elastic potential energy;
The elastic potential energy of an object is given by the formula;
Substituting into the equation, we have;
Elastic potential energy = 4.398 Joules.
<em>Therefore, the elastic potential energy of the spring is 4.398 Joules. </em>
Line up in a direction parallel to the magnetic field lines<span />
For reducing erosion of water banks, "Buffer strips" need to be used
In short, Your Answer would be option A
Hope this helps!
circular motion.
cent acc = r omega^2 ... omega is ang vel ... omega=2pi/T ,,,
9.8=rx(2pi/T)^2
if r is known, solve for T
Answer:
I dont either but I'm sorry and hopefully you figured it out