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Greeley [361]
3 years ago
7

A long string is pulled so that the tension in it increases by a factor of four. If the change in length is negligible, by what

factor does the wave speed change?
Physics
1 answer:
rusak2 [61]3 years ago
3 0

To solve this problem we will apply the concepts related to wave velocity as a function of the tension and linear mass density. This is

v = \sqrt{\frac{T}{\mu}}

Here

v = Wave speed

T = Tension

\mu = Linear mass density

From this proportion we can realize that the speed of the wave is directly proportional to the square of the tension

v \propto \sqrt{T}

Therefore, if there is an increase in tension of 4, the velocity will increase the square root of that proportion

v \propto \sqrt{4} = 2  

The factor that the wave speed change is 2.

You might be interested in
What is the elastic potential energy of a spring that is compressed a distance of 0.35 m and has a spring constant of 71.8 N/m?
Vitek1552 [10]

Answer:

P.E = 4.398 Joules.

Explanation:

Given the following data;

Spring constant, k = 71.8N/m

Displacement, x = 0.35m

To find the elastic potential energy;

The elastic potential energy of an object is given by the formula;

P.E = \frac {1}{2}kx^{2}

Substituting into the equation, we have;

P.E = \frac {1}{2}*71.8 *(0.35)^{2}

P.E = 35.9 * 0.1225

Elastic potential energy = 4.398 Joules.

<em>Therefore, the elastic potential energy of the spring is 4.398 Joules. </em>

3 0
3 years ago
A compass in a magnetic field will line up __________.
Anastaziya [24]
Line up in a direction parallel to the magnetic field lines<span />
5 0
4 years ago
Which of the following practices could help reduce erosion of water banks?
fredd [130]
For reducing erosion of water banks, "Buffer strips" need to be used

In short, Your Answer would be option A

Hope this helps!
4 0
3 years ago
Read 2 more answers
Please help, I really don't know
zubka84 [21]

circular motion.

cent acc = r omega^2 ... omega is ang vel ... omega=2pi/T ,,,

9.8=rx(2pi/T)^2

if r is known, solve for T


7 0
4 years ago
Ok sooo I need help I don’t understand this lol
Burka [1]

Answer:

I dont either but I'm sorry and hopefully you figured it out

3 0
3 years ago
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