State the condition under which a satellite would move with escape velocity
1 answer:
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Answer:
The distance traveled by the balloon is 10.77 m
Explanation:
velocity of the ball, = 2 m/s south
velocity of the air, = 5 m/s west
To determine the distance the balloon will travel after 2 seconds, first determine the resultant velocity of the balloon.
| 2m/s
|
|
↓
5m/s ←------------------
the two velocities forms a right angled triangle and the resultant will be the hypotenuses side of the triangle.
R² = 5² + 2²
R² = 29
R = √29
R = 5.385 m/s
The distance traveled by the balloon is calculated as;
d = R x t
where;
t is time of the motion = 2 seconds
d = 5.385 x 2
d = 10.77 m
Therefore, the distance traveled by the balloon is 10.77 m.
- The angle between the two vectors is 90° .
- The dot product of two vectors .
- The cross product of two vectors .
⚡ Let and
are the two vectors .
✍️ We have know that,
Where,
- θ = 90°
- cos 90° = <u>0</u>
[1] The dot product of two vectors is “ <u>0</u> ” .
✍️ We have know that,
Where,
- θ = 90°
- sin 90° = <u>1</u>
[2] The cross product of two vectors is “ <u>ab</u> ” .