Answer:
250.05 J
Explanation:
From the question given above and, the following data were obtained:
Mass (m) = 0.7 kg
Kinetic energy (KE) = 250.1 J
Potential energy (PE) =?
Next, we shall determine the velocity of the ball. This can be obtained as follow:
Mass (m) = 0.7 kg
Kinetic energy (KE) = 250.1 J
Velocity (v) =?
KE = ½mv²
250.1 = ½ × 0.7 × v²
250.1 = 0.35 × v²
Divide both side by 0.35
v² = 250.1 / 0.35
Take the square root of both side
v = √(250.1 / 0.35)
v = 26.73 m/s
Next, we shall determine the maximum height reached by the ball. This can be obtained as follow:
Initial velocity (u) = 26.73 m/s
Final velocity (v) = 0 m/s (at maximum height)
Acceleration due to gravity (g) = 9.8 m/s²
Maximum height (h) =.?
v² = u² – 2gh (since the ball is going against gravity)
0² = 26.73² – (2 × 9.8 × h)
0 = 714.4929 – 19.6h
Collect like terms:
0 – 714.4929 = – 19.6h
– 714.4929 = – 19.6h
Divide both side by –19.6
h = –714.4929 / –19.6
h = 36.45 m
Finally, we shall determine the potential energy of the ball at the maximum height. This can be obtained as follow:
Mass (m) = 0.7 kg
Acceleration due to gravity (g) = 9.8 m/s²
Maximum height (h) = 36.45 m
Potential energy (PE) =?
PE = mgh
PE = 0.7 × 9.8 × 36.45
PE = 250.05 J
Thus, the potential energy at the maximum height is 250.05 J.
