The change of color. Each color has a different wavelength therefore a different frequency.
Answer:
<h3>The binding energy of sodium Na=<em>5.407791×10⁹J</em></h3>
Explanation:
<h3>Greetings !</h3>
Binding energy, amount of energy required to separate a particle from a system of particles or to disperse all the particles of the system. Binding energy is especially applicable to subatomic particles in atomic nuclei, to electrons bound to nuclei in atoms, and to atoms and ions bound together in crystals.
<h2>Formula : Eb=(Δm)c²</h2><h3>where:Eb= binding energy</h3><h3> .Δm= mass defect(kg)</h3><h3> c= speed of light 3.00×10⁸ms¯¹</h3><h2 /><h3>
<u>Given</u><u> </u><u>values</u></h3>
- m= 18.02597
- c=3.00×10⁸ms¯¹
<h3><u>required </u><u>value</u></h3>
<h3><u>Solution:</u></h3>
- Eb=(Δm)c²
- Eb=(18.02597)*(3.00*10⁸ms¯¹
- Eb=5.407791*10⁹J
Answer:
f = 692 N
Explanation:
given data:
f =800N
a =1.2 m s^{2}
m= 90 kg
from newton's second law
net force 
therefore we have from above equation
ma =F - f
putting all value to get force of friction
1.2*90 = 800 - f
f = 692 N
Answer:
Explanation:
For answer this we will use the law of the conservation of the angular momentum.
so:
where 
is the moment of inertia of the merry-go-round, 
is the initial angular velocity of the merry-go-round, 
is the moment of inertia of the merry-go-round and the child together and 
is the final angular velocity.
First, we will find the moment of inertia of the merry-go-round using:
I = 
I = 
I = 359.375 kg*m^2
Where 
is the mass and R is the radio of the merry-go-round
Second, we will change the initial angular velocity to rad/s as:
W = 0.520*2
rad/s
W = 3.2672 rad/s
Third, we will find the moment of inertia of both after the collision:
Finally we replace all the data:
Solving for :
I assume the block plows into the bank of sand with a velocity of 6 m/s and comes to a stop in 2 s.
