Answer: 63 miles per hour
i think
Explanation:
Answer:
1.58 W
Explanation:
Since the sound spreads uniformly in all directions, it must be in a form of a circle with radius of 12 m. So the area of the circle is
![A = \pi r^2 = \pi 12^2 = 452.389 m^2](https://tex.z-dn.net/?f=A%20%3D%20%5Cpi%20r%5E2%20%3D%20%5Cpi%2012%5E2%20%3D%20452.389%20m%5E2)
From the intensity of the sound we can calculate the power at 12 m
![P = AI = 452.389 * 3.5\times10^{-3} = 1.58 W](https://tex.z-dn.net/?f=P%20%3D%20AI%20%3D%20452.389%20%2A%203.5%5Ctimes10%5E%7B-3%7D%20%3D%201.58%20W)
Answer:
Los 0.0416km
esto se debe a que transponemos la fórmula acelerada y obtenemos Distancia = velocidad × tiempo
también recuerda transponer los segundos a horas viendo que la velocidad es por hora
También tenga en cuenta que no hablo español, así que esto fue extremadamente difícil
culto
The force tending to lift the load (vertical force) is equal to <u>22.5N.</u>
Why?
Since the boy is pulling a load (150N) with a string inclined at an angle of 30° to the horizontal, the total force will have two components (horizontal and vertical component), but we need to consider the given information about the tension of the string which is equal to 105N.
We can calculate the vertical force using the following formula:
![VerticalForce=Force*Sin(30\° )=(BoysForce-StringForce)*\frac{1}{2}\\\\VerticalForce=(150N-105N)*\frac{1}{2}=VerticalForce=45N*\frac{1}{2}=22.5N](https://tex.z-dn.net/?f=VerticalForce%3DForce%2ASin%2830%5C%C2%B0%20%29%3D%28BoysForce-StringForce%29%2A%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5CVerticalForce%3D%28150N-105N%29%2A%5Cfrac%7B1%7D%7B2%7D%3DVerticalForce%3D45N%2A%5Cfrac%7B1%7D%7B2%7D%3D22.5N)
Hence, we can see that <u>the force tending to lift the load</u> off the ground (vertical force) is equal to <u>22.5N.</u>
Have a nice day!