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Viktor [21]
3 years ago
7

What is the y-intercept of the equation?

Mathematics
2 answers:
garik1379 [7]3 years ago
6 0
The y-intercept would be 5
Tema [17]3 years ago
4 0

Answer:

5

Step-by-step explanation:

Y=-3x+5

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Round to the nearest given place.<br> 1.80431<br><br> thousandths
rodikova [14]
In order to round a number to the nearest thousandths, we have to check the number in the ten thousandths place:
1- If the number in the ten thousandths is less than 5, then the thousandths number will remain the same and all numbers after it will be converted to zeroes.
2- If the number in the ten thousandths is equal to or greater than 5, then the thousandths number will be incremented by 1 and all numbers after it will be converted to zeroes.

Applying this to the given number: 
<span>1.80431
</span>The number in the ten thousandths position is 3 which is less than 5.
Therefore, rounding <span>1.80431 to the nearest thousandths will be:
</span>1.80400 which is equivalent to 1.804
5 0
3 years ago
Jennifer buys school supplies for $12.16. The sales tax is 7.25% what is the amount of tax for Jennifer’s purchases? Show how yo
11111nata11111 [884]

Answer:

$12.16 x .0725 = .8816 round is .88 cents

Step-by-step explanation:

change % to decimal and multiply

7 0
3 years ago
Read 2 more answers
Need help simplifying this
diamong [38]

The simplified answer is \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}.

<u>Step-by-step explanation:</u>

$\frac{3 y+2 x}{z+2 x}-\frac{2 y-3 x}{3 x+y}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}

To add or subtract denominators of the fraction must be same.

If it is not the same, we must take LCM of the denominators. and so we can add the fractions.

To make the denominator same multiply the 1st term (\frac{3x+y}{3x+y}) and 2nd term by (\frac{z+2x}{z+2x})

= \frac{(3 y+2 x)(3 x+y)}{(z+2 x)(3 x+y)}-\frac{(2 y-3 x)(z+2 x)}{(3 x+y)(z+2 x)}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}

LCM of the denominators is 6x²+ 3xz + 2xy +yz.

Multiply the factors in the numerator.

= \frac{\left(6 x^{2}+3 y^{2}+11 x y\right)}{(z+2 x)(3 x+y)}-\frac{\left(2 y z+4 x y-3 x z-6 x^{2}\right)}{(3 x+y)(z+2 x)}-\frac{2 z y+6 x z}{6 x^{2}+3 x z+2 x y+y z}

Now, the denominators are same, you can subtract it.

= \frac{\left(6 x^{2}+6 x^{2}+11 x y-4 x y-2 y z-2 y z+3 x z-6 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

= \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

Thus the simplified solution is  \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

4 0
4 years ago
Elena makes banana bread and nut bread to sell at the market. A loaf of banana bread requires 2 cups of flour and 2 eggs. A loaf
9966 [12]

Let x be the number of loaves of banana bread and y be the number of loaves of nyt bread Elena makes.

1. A loaf of banana bread requires 2 cups of flour and 2 eggs, then x loaves require 2x cups of flour and 2x eggs.

2. A loaf of nut bread takes 3 cups of flour and 1 egg, then y loaves require 3y cups of flour and y eggs.

3. Elena has 12 cups flour, then

2x+3y≤12.

4. Elena has 8 eggs, then

2x+y≤8.

5. If she makes $1.50 profit per loaf of banana bread and $2 per loaf of nut bread, then she makes total profit of $(1.50x+2y).

The solution of system of two inequalities

\left\{\begin{array}{l}2x+3y\le 12\\2x+y\le 8\end{array}\right.

is represented in the attached diagram.

The maximal profit can be obtained at point (3,2), where

\$(1.50\cdot 3+2\cdot 2)=\$8.5.

Answer: correct choice is C (Elena could make 3 loaves of banana bread and 2 loaves of nut bread to maximize her profit)

6 0
4 years ago
Read 2 more answers
Can any help with this
Lisa [10]
78.4

To find this, set up a ratio like formula:

28/15 to x/42

The multiply 28 by 42 and divide by 15 to receive your final answer.

Hope this helps!
5 0
3 years ago
Read 2 more answers
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