All categories

3 years ago

Which is most applicable when continuous inspection is used? I-chart, P-chart, c-chart C-bar chart

Mathematics

1 answer:

Zepler [3.9K]3 years ago

8 0

Answer:

I - Chart

Step-by-step explanation:

The charts are used for representation of inspected data in to structure way which helps understand the changes easily. I chart is usually used when there is continuous inspection for the data. This type of chart used to monitor the process when measuring data at regular intervals.

You might be interested in

$1689 invested for 4 years at 3% compounded annually ?

Ira Lisetskai [31]

The amount gotten after $1689 invested for 4 years at 3% compounded annually is $1901

The amount of money gained after an investment is compounded is given by:

$A=P(1+\frac{r}{n} )^{nt}$

Where P is principal, A is the final amount, r is the rate, n is the number of times compounded per period and t is the time

Given that P = $1689, t = 4, r = 3% = 0.03, n = 1, hence:

$A=P(1+\frac{r}{n} )^{nt}\\\\A=1689(1+\frac{0.03}{1} )^{4*1}\\\\A=\$1901$

The amount gotten after $1689 invested for 4 years at 3% compounded annually is $1901

Find out more at: brainly.com/question/14295570

5 0

2 years ago

An insurance company offers its policyholders a number of different premium payment options. For a randomly selected policyholde

n200080 [17]

Answer:

(a)

$\begin{array}{cccccc}x & {1} & {3} & {4} & {6} & {12} \ \\ P(x) & {0.30} & {0.10} & {0.05} & {0.15} & {0.40} \ \end{array}$

(b)

$P(3 \le x \le 6) = 0.30$

$P(4 \le x)=0.60$

Step-by-step explanation:

Given

$F(x) = \left[\begin{array}{ccc}0& x$

Solving (a): The pmf

This means that we list out the probability of each value of x.

To do this, we simply subtract the current probability value from the next.

So, we have:

$\begin{array}{cccccc}x & {1} & {3} & {4} & {6} & {12} \ \\ P(x) & {0.30} & {0.10} & {0.05} & {0.15} & {0.40} \ \end{array}$

The calculation is as follows:

$0.30 - 0 = 0.30$

$0.40 - 0.30 = 0.10$

$0.45 - 0.40 = 0.05$

$0.60 - 0.45 = 0.15$

$1 - 0.60 = 0.40$

The x values are gotten by considering where the equality sign is in each range.

$1 \le x < 3$ means $x = 1$

$3 \le x < 4$ means $x = 3$

$4 \le x < 6$ means $x=4$

$6 \le x < 12$ means $x = 6$

$12 \le x$ means $x = 12$

Solving (b):

$(i)\ P(3 \le x \le 6)$

This is calculated as:

$P(3 \le x \le 6) = F(6) - F(3-)$

From the given function

$F(6)= 0.60$

$F(3-) = F(1) = 0.30$

So:

$P(3 \le x \le 6) = 0.60 - 0.30$

$P(3 \le x \le 6) = 0.30$

$(ii)\ P(4 \le x)$

This is calculated as:

$P(4 \le x)=1 - F(4-)$

$P(4 \le x)=1 - F(3)$

$P(4 \le x)=1 - 0.40$

$P(4 \le x)=0.60$

8 0

3 years ago

I need help I need help I need help I need help I need help i need help I need help

beks73 [17]

Answer:

5) The midrange is 19.5ºF

6) The midrange is 67.5º

Explanation:

The problem tell us how to calculate the midrange.

In (5) the minimum and maximum values are given (-6ºF and 45ºF, respectively). Using the formula:

$Midrange=\frac{-6+45}{2}=\frac{39}{2}=19.5ºF$

In (6), we need to find the minimum and maximum values from a list of them. We can see that the minimum is 58º and the maximum 77º

Then:

$Midrange=\frac{58+77}{2}=\frac{135}{2}=67.5º$

5 0

1 year ago

The coefficient of the term 76x2 is: (2 is the exponent of 76x)

Lady_Fox [76]

The definition of a coefficient is the number BEFORE the variable. So in 76x^2, the coefficient is 76.

6 0

3 years ago

one moving company charges $800 plus $16 per hour another moving company charges $720 plus $21 an hour at what number of hours w

Gekata [30.6K]

800 + 16x = 720 + 21x. Cancel out the 720 to get 80 + 16x = 21x. Subtract 16x from both sides to get 80 = 5x. Divide by 5 to get 16 = x, or x = 16. 16 hours. The charge is 800 + 16(16), = 720 + 21(16) which = 800 + 256 = 720 + 336 which = 1,056 = 1,056. Hope this helped!

6 0

3 years ago