Answer:
Left column:
1 & 2
right column:
1 & 2
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Answer: 4/9
Step-by-step explanation:
The probability that annie picks a duck Pt= the probability of picking a duck without accounting for the added one (Po)+ probability of picking the added bird and it's a duck(Pi)
Pt = Po+Pi
Since the total number of birds in the right pond is 10 after the addition of one by john
Po= 4/10
Pi= the of john adding a duck × the probability of annie picking the added bird
Pi= 4/9 × 1/10
Pi = 4/90
Pt= 4/10 + 4/90
Pt = (36+4)/90
Pt=40/90
Pt= 4/9
(This implies that the probability of picking a duck remain the same even after the addition of one bird from the left ponds because they both have equal proportions of duck and geese i.e the initial number of duck and geese in both right and left ponds are 4 and 5 respectively)
Thanks.
The equation of the circle:
(h, k) - center
r - radius
We have:
Substitute:
We have this equation to start with: m/n = 5.5. To achieve the desired equation, you need to multiply the entire equation by n, giving you this equation: m = 5.5n. Hope this helps!
Answer:
(E) 0.71
Step-by-step explanation:
Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.
So, the probability that the student has a GPA lower than 3.5 and is not taking any AP classes is calculated as:
P(A'∩B') = 1 - P(A∪B)
it means that the students that have a GPA lower than 3.5 and are not taking any AP classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.
Therefore, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled in at least one AP class is 0.12
So, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = 0.25 + 0.16 - 0.12
P(A∪B) = 0.29
Finally, P(A'∩B') is equal to:
P(A'∩B') = 1 - P(A∪B)
P(A'∩B') = 1 - 0.29
P(A'∩B') = 0.71
