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slamgirl [31]
3 years ago
12

CALCULATE THE VOLUME OF 16 g OF OXYGEN GAS AT S.T.P?

Chemistry
1 answer:
White raven [17]3 years ago
7 0

Answer:

To calculate the volume we must first find the number of moles

Number of moles (n ) = mass / Molar mass (M)

Since oxygen is diatomic

M of oxygen = 16 × 2 = 32g/mol

n = 16 / 32 = 0.5mol

Next we use the formula

V = n × V(dm³)

where V is the volume

V(dm³) is the volume of 1 mole of a substance at s.t.p which is

22.4dm³

Volume of oxygen gas at s.t.p is

0.5 × 22.4dm³

= 11.20dm³

Hope this helps you

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Explanation:

The given data is as follows.

       Volume of lake = 15 \times 10^{6} m^{3} = 15 \times 10^{6} m^{3} \times \frac{10^{3} liter}{1 m^{3}}

        Concentration of lake = 5.6 mg/l

Total amount of pollutant present in lake = 5.6 \times 15 \times 10^{9} mg

                                                                    = 84 \times 10^{9} mg

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Flow rate of river is 50 m^{3} sec^{-1}

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Therefore, total concentration of lake after 1 day = \frac{131936 \times 10^{6}}{1.938 \times 10^{10}}mg/ l

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       L_{o} = 6.8078

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