Answer:
D. -1882J
Explanation:
We can solve the energy released in a chemical reaction in an aqueous medium using the equation:
Q = -m*C*ΔT
<em>Where Q is energy (In J),</em>
<em>m is mass of water (45.00g)</em>
<em>C is specific heat of water (4.184J/g°C)</em>
<em>And ΔT is change in temperature (25.00°C - 15.00°C = 10.00°C)</em>
<em />
Replacing:
Q = -45.00*4.184J/g°C*10.00°C
Q = -1882J
Right answer is:
<h3>D. -1882J</h3>
<em />
Dimethyl amine is Base. The basic character of it is due to the presence of lone pair of electron on nitrogen atom. The strength of amines is basically due to the presence of alkyl group attached to nitrogen atom. These alkyl groups donates electron to nitrogen atom hence increasing electron density on nitrogen and increasing its basic character.
When dimethylamine ( Kb = 5.9 × 10⁻⁴) is reacted with water it abstracts proton from water molecule convertion it into Hydroxide Ion (i.e ⁻OH). The reaction is as follow,
(CH₃)₂N + H₂O → (CH₃)₂N⁺H + ⁻OH
Answer:
There are 3, 64 moles of NaCl.
Explanation:
First we calculate the mass of 1 mol of NaCl, starting from the atomic weights of Na and Cl obtained from the periodic table. Then we calculate themoles in 213 grams of NaCl, making a simple rule of three:
Weight NaCl= Weight Na + Weight Cl = 23 g + 35, 5 g= 58, 5 g/ mol
58,5 g ------1 mol NaCl
213 g---------x= (213 g x 1 mol NaCl)/ 58, 5 g= <em>3, 64 mol NaCl</em>
