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sveticcg [70]
4 years ago
11

What is the solution of 3sqrt(x+8=-4

Mathematics
2 answers:
ValentinkaMS [17]4 years ago
6 0
Solve for x:
3 sqrt(x + 8) = -4

Divide both sides by 3:
sqrt(x + 8) = -4/3

Raise both sides to the power of two:
x + 8 = 16/9

Subtract 8 from both sides:
x = -56/9

3 sqrt(x + 8) ⇒ 3 sqrt(8 - 56/9) = 4:
So this solution is incorrect

The solution is incorrect:
Answer:  (no solutions)
creativ13 [48]4 years ago
3 0
Hello there!

3 \sqrt{x+8}=-4

So this is the equation we have, and I'm guessing we have to solve for the value of x.

Let's divide both sides by 3.

\sqrt{x+8}=-4/3

Square both sides to get rid of the square root.

x+8=(-4/3)^2
x+8=16/9

Subtract both sides by 8.

x=16/9-8=16/9-72/9=-56/9
x=-56/9

<span>Let’s test if this is an extraneous solution by plugging this value into the equation.

3 \sqrt{-56/9+8}
=4

This does not produce the desired result, which was supposed to be -4. Thus, x=-56/9 is an extraneous solution, so there are no solutions to this equation.
</span>
I hope this helps and have an awesome day! :)
~AgentCozmo4, Moderator
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A fried chicken franchise finds that the demand equation for its new roast chicken product, "Roasted Rooster," is given by p = 4
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Answer:

1. q=(\dfrac{45}{p})^{\frac{2}{3}}

2. E_d=-\dfrac{2}{3}

Step-by-step explanation:

The given demand equation is

p=\dfrac{45}{q^{1.5}}

where p is the price (in dollars) per quarter-chicken serving and q is the number of quarter-chicken servings that can be sold per hour at this price.

Part 1 :

We need to Express q as a function of p.

The given equation can be rewritten as

q^{1.5}=\dfrac{45}{p}

Using the properties of exponent, we get

q=(\dfrac{45}{p})^{\frac{1}{1.5}}      [\because x^n=a\Rightarrow x=a^{\frac{1}{n}}]

q=(\dfrac{45}{p})^{\frac{2}{3}}

Therefore, the required equation is q=(\dfrac{45}{p})^{\frac{2}{3}}.

Part 2 :

q=(45)^{\frac{2}{3}}p^{-\frac{2}{3}}

Differentiate q with respect to p.

\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(p^{-\frac{2}{3}-1}})

\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(p^{-\frac{5}{3}})

\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})

Formula for price elasticity of demand is

E_d=\dfrac{dq}{dp}\times \dfrac{p}{q}

E_d=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})\times \dfrac{p}{(45)^{\frac{2}{3}}p^{-\frac{2}{3}}}

Cancel out common factors.

E_d=(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})\times \dfrac{p}{p^{-\frac{2}{3}}}

Using the properties of exponents we get

E_d=-\dfrac{2}{3}(p^{-\frac{5}{3}+1-(-\frac{2}{3})})

E_d=-\dfrac{2}{3}(p^{0})

E_d=-\dfrac{2}{3}

Therefore, the price elasticity of demand is -2/3.

3 0
3 years ago
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