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dybincka [34]
3 years ago
5

I need help with this.

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
5 0

Answer:

The volume of a triangular pyramid is 24 cubic inches. The base is a right triangle with a length

of 4 inches and height of 3 inches. What is the height of the pyramid, in inches?

Step-by-step explanation:

The volume of a triangular pyramid is 24 cubic inches. The base is a right triangle with a length

of 4 inches and height of 3 inches. What is the height of the pyramid, in inches?

The volume of a triangular pyramid is 24 cubic inches. The base is a right triangle with a length

of 4 inches and height of 3 inches. What is the height of the pyramid, in inches?

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A clown creates an equation that relates his data of each child´s head size to the length of the balloon he needs to make them a
Mashcka [7]

Answer:

If x is the size of the child's head, 5 times that would be 5x and "plus 4/5" is + 4/5 so the equation is y = 5x + 4/5.

5 0
3 years ago
Find all possible values of α+
const2013 [10]

Answer:

\rm\displaystyle  0,\pm\pi

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when <u>tanα+tanβ+tanγ = tanαtanβtanγ</u><u> </u>to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

\rm\displaystyle  \tan( \alpha )  +  \tan( \beta ) =  \tan( \alpha )  \tan( \beta )  \tan( \gamma )  -  \tan( \gamma )

factor out tanγ:

\rm\displaystyle  \tan( \alpha )  +  \tan( \beta ) =   \tan( \gamma ) (\tan( \alpha )  \tan( \beta ) -  1)

divide both sides by tanαtanβ-1 and that yields:

\rm\displaystyle   \tan( \gamma ) =  \frac{ \tan( \alpha )  +  \tan( \beta ) }{ \tan( \alpha )  \tan( \beta )    - 1}

multiply both numerator and denominator by-1 which yields:

\rm\displaystyle   \tan( \gamma ) =   -  \bigg(\frac{ \tan( \alpha )  +  \tan( \beta ) }{ 1 - \tan( \alpha )  \tan( \beta )   } \bigg)

recall angle sum indentity of tan:

\rm\displaystyle   \tan( \gamma ) =   -  \tan( \alpha  +  \beta )

let α+β be t and transform:

\rm\displaystyle   \tan( \gamma ) =   -  \tan( t)

remember that tan(t)=tan(t±kπ) so

\rm\displaystyle   \tan( \gamma ) =    -\tan(   \alpha   +\beta\pm k\pi )

therefore <u>when</u><u> </u><u>k </u><u>is </u><u>1</u> we obtain:

\rm\displaystyle   \tan( \gamma ) =    -\tan(   \alpha   +\beta\pm \pi )

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

\rm\displaystyle   \tan( \gamma ) =    \tan(   -\alpha  -\beta\pm \pi )

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

\rm\displaystyle  \gamma  =      -   \alpha   -  \beta \pm \pi

isolate -α-β to left hand side and change its sign:

\rm\displaystyle \alpha  +  \beta  +   \gamma  =  \boxed{ \pm \pi  }

<u>when</u><u> </u><u>i</u><u>s</u><u> </u><u>0</u>:

\rm\displaystyle   \tan( \gamma ) =    -\tan(   \alpha   +\beta \pm 0 )

likewise by Opposite Angle Identity we obtain:

\rm\displaystyle   \tan( \gamma ) =    \tan(   -\alpha   -\beta\pm 0 )

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

\rm\displaystyle  \gamma  =      -   \alpha   -  \beta \pm 0

isolate -α-β to left hand side and change its sign:

\rm\displaystyle \alpha  +  \beta  +   \gamma  =  \boxed{ 0  }

and we're done!

8 0
3 years ago
Read 2 more answers
I am confused on how to do this
babymother [125]
So, u would start by expanding the bracket and ignoring the 2 at the moment.
(x+9)(x+9)= x^2-18x+81(using the foil method!

Then u would put 2 at the front to get:
2(x^2+18x+81)
= 2x^2+36x+162
4 0
3 years ago
Name a pair of perpendicular lines: <br>is line BC and AJ perpendicular: explain ​
wel
A pair of perpendicular lines would be line CF and line AJ.

Line BC and line AJ are NOT perpendicular because when a pair of lines are perpendicular, all angles become 90 degrees. It is obvious, in the case, if you were to slide line BC on top of line AJ, the angles will not equal 90 degrees.
8 0
3 years ago
May someone help me out with this please. thanks
dmitriy555 [2]
Since your looking for the increase you can take the number from 2004
and 2014 and turn it into a fraction
54/135
now that you've done that times it by 100 like this

54/135 x 100=
40

and that will give you the percentile which is:
40%

Hope that helps X3
4 0
3 years ago
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