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LUCKY_DIMON [66]
3 years ago
7

CHEM

Chemistry
2 answers:
castortr0y [4]3 years ago
3 0
Molarity = moles / liter

a) M = 2/4 = 0.5 M

b) Moles = 4/(30 + 16 + 1)
= 0.085
M = 0.085 / 2 = 0.0425 M

c) Moles = 5.85 / (23 + 35.5)
= 0.1
M = 0.1 / 0.4
= 0.25 M
Dmitrij [34]3 years ago
3 0
Molarity =moles of solute /volume of solution. A.) Molarity of glucose =moles of glucose /volume of solution =2/4 = 0.5 M B.) No of moles of KOH= weight of KOH / molecular weight of KOH = 4/ 56.10 =0.07 moles. Therefore, Molarity of KOH =moles of KOH /volume of solution = 0.07/2 = 0.035M. C.) No of moles of NaCl = weight of NaCl/ molecular weight of NaCl = 5.85/58.5 = 0.1moles. Therefore, Molarity of NaCl = moles of NaCl /volume of solution = 0.1/ 400 x 10^-3 = 0.25M
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How many moles of hcl are present in 40.0 ml of a 0.035 m solution?
Elden [556K]

Answer:

0.0014 moles is present in 40cm³ of 0.035M of HCl solution

Explanation:

Molarity = 0.035M

V = 40.0mL

1mL = 1cm³

V = 40cm³

0.035 moles = 1000cm³

X moles is present in 40cm³

X = (40 * 0.035) / 1000

X = 0.0014moles

0.0014 moles is present in 40cm³ of solution

8 0
3 years ago
Suppose you held two magnets a short distance apart,then let go. what would happen?
Murljashka [212]
The two magnets ought to join together given that at least, if not both, have a strong enough magnetic force to do so.
4 0
3 years ago
Read 2 more answers
How many number of moles are present in 200. g of sodium bicarbonate (NaHCO3)
nikdorinn [45]

You can solve this problem through dimensional analysis.

First, find the molar mass of NaHCO3.

Na = 22.99 g

H = 1.008 g

C = 12.01 g

O (3) = 16 (3) g

Now, add them all together, you end with with the molar mass of NaHCO3.

22.99 + 1.008 + 12.01 + 16(3) = 84.008 g NaHCO3. This number means that for every mole of NaHCO3, there is 84.008 g NaHCO3. In simpler terms, 1 mole NaHCO3 = 84.008 g NaHCO3.

After finding the molar mass of sodium bicarbonate, now you can use dimensional analysis to solve for the number of moles present in 200. g of sodium bicarbonate.

200. g NaHCO_3 * \frac{1 mole NaHCO_3}{84.008 g NaHCO_3}

Cross out the repeating units which are g NaHCO3, and the remaining unit is mole NaHCO3

200.  * 1 = 200

200/ 84.008 = 2.38

Notice how there are only 3 sig figs in the answer. This is because the given problem only gave three sig figs.

Your final answer is 2.38 mol NaHCO3.

8 0
3 years ago
A spectator ion is (Select all that apply.) a. an ionic component of a reactant that is unchanged by the reaction your eye, b. c
DENIUS [597]

Correct Question:

A spectator ion is (Select all that apply.)

- a piece of french fry contaminating the reaction mixture

- an ionic component of a reactant that is unchanged by the reaction

-in this experiment, nitrate ion

- your eye, carefully watching the progress of the reaction

Answer:

- an ionic component of a reactant that is unchanged by the reaction

Explanation:

A spectator ion is an ion that exists as a reactant and a product in a chemical equation. A spectator ion is one that exists in the same form on both the reactant and product sides of a chemical reaction.

Spectator ions are ions that are present in a solution but don't take part in the reaction. When reactants dissociate into ions, some of the ions may combine to form a new compound. The other ions don't take part in this chemical reaction and are therefore called spectator ions.

The correct option is therefore the option;

- an ionic component of a reactant that is unchanged by the reaction

5 0
3 years ago
If a gas occupies a volume of 950 mL at standard temperature, what volume will it
n200080 [17]
Voulme 1= 950 mL
Volume 2= ?
Temperature 1 = 25 C
Temperature 2 = 50 C
Convert your temperature to Kelvin
C+273=K
Temperature 1 = 25 C + 273 = 298 K
Temperature 2 = 50 C + 273 = 323 K

Plug in to the Formula
950 mL/298 K = ? / 323 K

Rearrange the formula to make one to solve for what is missing.
To get 323 K out of the denominator multiply by it.
Making it
950 mL x 323 K / 298 K = ?

Plug it in
950 mL x 323 K / 298 K = 1027.9 mL
3 0
3 years ago
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