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LUCKY_DIMON [66]
3 years ago
7

CHEM

Chemistry
2 answers:
castortr0y [4]3 years ago
3 0
Molarity = moles / liter

a) M = 2/4 = 0.5 M

b) Moles = 4/(30 + 16 + 1)
= 0.085
M = 0.085 / 2 = 0.0425 M

c) Moles = 5.85 / (23 + 35.5)
= 0.1
M = 0.1 / 0.4
= 0.25 M
Dmitrij [34]3 years ago
3 0
Molarity =moles of solute /volume of solution. A.) Molarity of glucose =moles of glucose /volume of solution =2/4 = 0.5 M B.) No of moles of KOH= weight of KOH / molecular weight of KOH = 4/ 56.10 =0.07 moles. Therefore, Molarity of KOH =moles of KOH /volume of solution = 0.07/2 = 0.035M. C.) No of moles of NaCl = weight of NaCl/ molecular weight of NaCl = 5.85/58.5 = 0.1moles. Therefore, Molarity of NaCl = moles of NaCl /volume of solution = 0.1/ 400 x 10^-3 = 0.25M
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When 60 mL of 0.22 M NH4Cl is added to 60 mL of 0.22 M NH3, relative to the pH of the 0.10 M NH3 solution the pH of the resultin
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Answer:

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Explanation:

The equilibrium of NH3 in water is:

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Now, to find the pH of the NH4Cl and NH3 we need to use H-H equation for bases:

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<em>Where pKb is -log Kb = 4.74 and [] are moles of both compounds.</em>

<em />

Moles of [NH4⁺] = [NH3] = 60mL, 0.060L*0.22M = 0.0132moles:

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Read 2 more answers
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