Answer:
O(Oxygen)
Explanation:
Oxygen or O among the given options has the highest electronegativity of 3.5 as compared to 2.4 of sulfur. Thus, there is a lesser attraction in the bonds of Sulfur. <u>The other two elements Al(Aluminium) and Cu are less electronegative than Sulfur and Oxygen as they are metals and possess electropositivity while the latter displays more electronegativity due to being non-metals</u>. Hence, Oxygen is the answer.
When the antimatter is atomic antihydrogen, a small amount of it is mixed with excess atomic hydrogen (gathered from interstellar space during flight).
<h3>What is antimatter ?</h3>
According to contemporary physics, antimatter is described as being made up of the opposite particles from "ordinary" matter, or their "partners." Only a few nanograms of antiparticles have been created artificially, but tiny quantities of antiparticles are produced every day at particle accelerators and in natural processes like cosmic ray collisions and some types of radioactive decay. However, only a small portion of these antiparticles have been successfully bound together in experiments to form antiatoms. Antimatter has never been built in a macroscopic amount due to its extremely high cost, complexity in synthesis, and handling.
A particle and its antiparticle, such as a proton and an antiproton, theoretically have the same mass but the opposite electric charge and other variations in quantum numbers.
To learn more about antimatter from the given link:
brainly.com/question/518346
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Answer:
Explanation:
The<em> heat</em> to <em>vaporize</em> a l<em>iquid</em> is equal to the amount of liquid in moles multiplied by the specific <em>heat of vaporiztion</em> per mole.
First, calculate the number of moles in 35.5g of <em>butane</em>.
- Molar mass of butane: 58.124 g/mol
- Number of moles = mass in grams/molar mass
- Number of moles = 35.5g / 58.124g/mol = 0.6107632mol
Now, calculate the heat to vaporize that amount of <em>liquid butane</em>:
- Heat = number of moles × specific heat of vaporization
- Heat = 0.6107632mol × 21.3kJ/mol = 13.0 kJ
The answer must be reported with 3 significant figures.
Answer:
The complete question is:
Question: What disorder is indicated by these findings? A client comes to the emergency department with status asthmaticus. His respiratory rate is 48 breaths/minute, and he is wheezing. An arterial blood gas analysis reveals a pH of 7.52, a partial pressure of arterial carbon dioxide (PaCO2) of 30 mm Hg, PaO2 of 70 mm Hg, and bicarbonate (HCO3−) of 26 mEq/L.
A. Metabolic acidosis
B. Respiratory acidosis
C. Metabolic alkalosis
D. Respiratory alkalosis
Answer: The correct answer is:
D. Respiratory alkalosis
Explanation:
In Respiratory alkalosis the Partial Pressure of Arterial Carbondioxide (PaCO2) become decreased (i.e. less than 35 mm Hg) and the pH of blood become increased (i.e. more than 7.45). Alveolar hyperventilation causes respiratory alkalosis.
Alveolar hyperventilation occurs when alveolar ventilation is increased than the arterial carbondioxide tension and carbondioxide production.
Alveolar ventilation is the gaseous exchange between alveoli and the external environment.
Whereas, in metabolic acidosis, bicarbonate (HCO3) become decreased (i.e. less than 22 mEq/l and the pH of blood become decreased (i.e. less than 7.35); in respiratory acidosis, the pH of blood also become decreased (i.e. less than 7.35) and the PaCO2 become increased (i.e. more than 45 mm Hg); and in metabolic alkalosis, the bicarbonate (HCO3) become increased (i.e. more than 26 mEq/l and the pH become increased (i.e. more than 7.45).
D, all of these. (this is to reach the word limit on answers ignore it)
