Answer:
The constant of variation is 5.
Step-by-step explanation:
In direct variation, as y varies directly with x, the standard equation is
y = kx,
where k is the constant of variation.
In your case, we use R and S. R varies directly with S, so we have
R = kS
We know that when S = 16, R is 80, so we plug in those values and solve for k, the constant of variation.
R = kS
80 = k(16)
k = 80/16
k = 5
Answer:
Step-by-step explanation:
p + c = 110
p = c + 100
c + 100 + c = 110
2c + 100 = 110
2c = 110 - 100
2c = 10
c = 10/2
c = 5 .......cost of the phone case
p = c + 100
p = 5 + 100
p = 105 <=== cost of the phone
Answer:
False. 2/3 is positive so therefore, it would be increasing, not decreasing.
Step-by-step explanation:
Answer:
(-4,4)
Step-by-step explanation:
Answer:
a) 0.4121
b) $588
Step-by-step explanation:
Mean μ = $633
Standard deviation σ = $45.
Required:
a. If $646 is budgeted for next week, what is the probability that the actual costs will exceed the budgeted amount?
We solve using z score formula
= z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
For x = $646
z = 646 - 633/45
z = 0.22222
Probability value from Z-Table:
P(x<646) = 0.58793
P(x>646) = 1 - P(x<646) = 0.41207
≈ 0.4121
b. How much should be budgeted for weekly repairs, cleaning, and maintenance so that the probability that the budgeted amount will be exceeded in a given week is only 0.16? (Round your answer to the nearest dollar.)
Converting 0.16 to percentage = 0.16 × 100% = 16%
The z score of 16%
= -0.994
We are to find x
Using z score formula
z = (x-μ)/σ
-0.994 = x - 633/45
Cross Multiply
-0.994 × 45 = x - 633
-44.73 = x - 633
x = -44.73 + 633
x = $588.27
Approximately to the nearest dollar, the amount should be budgeted for weekly repairs, cleaning, and maintenance so that the probability that the budgeted amount will be exceeded in a given week is only 0.16
is $588
