The expression factorized completely is (h +2k)[(h+2k) + (2k-h)]
From the question,
We are to factorize the expression (h+2k)²+4k²-h² completely
The expression can be factorized as shown below
(h+2k)²+4k²-h² becomes
(h+2k)² + 2²k²-h²
(h+2k)² + (2k)²-h²
Using difference of two squares
The expression (2k)²-h² = (2k+h)(2k-h)
Then,
(h+2k)² + (2k)²-h² becomes
(h+2k)² + (2k +h)(2k-h)
This can be written as
(h+2k)² + (h +2k)(2k-h)
Now,
Factorizing, we get
(h +2k)[(h+2k) + (2k-h)]
Hence, the expression factorized completely is (h +2k)[(h+2k) + (2k-h)]
Learn more here:brainly.com/question/12486387
The largest number of Bird in the tree could be 14
Answer:
solution set of f(x) = g(x) is x∈{0,1}
Step-by-step explanation:
For all exponential functions b^x,
b^0 is always 1, and b^1 is always b.
f(x) = -3/4 x + 2
g(x) = (1/4)^x + 1
g(0) = 2, f(0) = 2
g(1) = 5/4, f(1) = 5/4
Answer:
they are both 0 since they would not appear on a graph
Step-by-step explanation:
1.) circumference: 2(pi)r (use the pi sign) Area: pi(r^2)
2.) circumference: 2(pi)5=31.4
area: pi(5^2)=78.5
I’m not sure ab number 3 sorry :\
