This question is incomplete, the complete question is;
A high-resistance material is used as an insulator between the conductors of a length of coaxial cable. The resistance material, which forms a hollow tube, has an inner radius a and an outer radius b, and the insulator provides a resistance R between the conductors. If a second insulator, made of the same material and having the same length, is made with double both the inner radius and the outer radius of the first, what resistance would it provide between the conductors
a) (In2)R
b) 4R
c) R/(In2)
d) 2R
e) R
Answer: Option e) R is the correct answer.
Explanation:
Given that;
Inner radius = a
Outer radius = b
Conical Cylinder
∫dR = ∫(edr/2πrL)
R = e/2πL In e |ᵇₐ
R = e/2πL In(b/a) ------------- let this be equation 1
Taking a look at the second cone
a' = 2a
b' = 2a
R' = e/2πL In(2b/2a)
{L = L'}
R' = e/2πL In(b/a) -------let this be equation 2
now lets compare the two equation
R = e/2πL In(b/a)
R' = e/2πL In(b/a)
so R' = R
Therefore Option e) R is the correct answer.
Step 1: Tell them to keep their eyes on the road.Step 2: Watch them to make sure they keep their eyes on the road.Step 3: Don't converse with them because you might risk distracting them.
It makes an awkward situation but it ensures that they'll feel so pressured to keep their eyes on the road or pull over so you can call a different ride.
Answer:
the waves will appear horizontally on the florescent screen because the y-plates have been removed
Solution :
Part A .
Given : The 
and 
components of the vector, d = 
degree left of -axis.
So the component is = -4 x sin (29°) = -1.939 km
component is = 4 x cos (29°) = 3.498 km
Part B
Given : The and components of the vector, 
, 
So the component is = -2 cm/s
component is = 0
Part C
Given : The and components of the vector, 
left of -axis.
So the component is = -13 x sin (36°) = -7.6412 
component is = -13 x cos (36°) = -10.517
Answer:
Energy of scattered photon is 232.27 keV.
Kinetic energy of recoil electron is 497.73 keV.
The recoil angle of electron is 13.40°
Explanation:
The energy of scattered photon is given by the relation :
.....(1)
Here E₁ is the energy of incident photon, E₂ is the energy of scattered photon, 
is mass of electron and θ is scattered angle.
Substitute 730 keV for E₁, 511 keV for and 120° for θ in equation (1).
E₂ = 232.27 keV
Kinetic energy of recoil electron is given by the relation :
K.E. = E₁ - E₂ = (730 - 232.27 ) keV = 497.73 keV
The recoil angle of electron is given by :
Substitute the suitable values in above equation.
= 13.40°
