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3 years ago

14

A carbon rod and a copper rod were hit alternately with a hammer. The carbon rod broke into pieces. Which property of carbon doe

s this observation indicate?

2 answers:

Kitty [74]3 years ago

7 0

Answer:

Carbon is a non metal

Explanation:

Non metals are brittle.

lesya692 [45]3 years ago

3 0

Answer:

Brittleness

Explanation:

hope this helps u

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DAILY REMINDER ~ YOU ARE LOVED BY SOMEONE I HOPE YOU HAVE A WONDERFUL DAY BABES!

Mila [183]

Answer:

THANK YOU

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Explanation:

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3 years ago

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The [OH-] of an aqueous solution is 3.5 x 10-5. What is the [H+]?

Sergeeva-Olga [200]

Answer: The concentration of hydrogen ion in the given solution is $2.81 \times 10^{-10}$ .

Explanation:

pOH of a solution is the negative logarithm of concentration of hydroxide ions.

Hence, if $[OH^{-}]$ is $3.5 \times 10^{-5}$ then its pOH value is calculated as follows.

$pOH = -log [OH^{-}]\\= -log (3.5 \times 10^{-5})\\= 4.45$

Now, the relation between pH and pOH is as follows.

pH + pOH = 14

pH + 4.45 = 14

pH = 14 - 4.45

= 9.55

And, pH is the negative logarithm of concentration of hydrogen ions. Hence, $[H^{+}]$ is calculated as follows.

$pH = -log [H^{+}]\\9.55 = -log [H^{+}]\\H^{+} = 2.81 \times 10^{-10}$

Thus, we can conclude that the concentration of hydrogen ion in the given solution is $2.81 \times 10^{-10}$ .

4 0

3 years ago

Substance ΔG°f(kJ/mol) M3O4(s) −8.80 M(s) 0 O2(g) 0 Consider the decomposition of a metal oxide to its elements, where M represe

baherus [9]

Answer:

The equilibrium constant is $K =0.02867$

The equilibrium pressure for oxygen gas is $P_{O_2} = 0.09367\ atm$

Explanation:

From the question we are told that

The equation of the chemical reaction is

$M_2 O_3 _{(s)} ----> 2M_{(s)} + \frac{3}{2} O_2_{(g)}$

The Gibbs free energy for $M_3 O_4_{(s)}$ is $\Delta G^o_{1} = -8.80 \ kJ/mol$

The Gibbs free energy for $M{(s)}$ is $\Delta G^o_{2} = 0 \ kJ/mol$

The Gibbs free energy for $O_2{(s)}$ is $\Delta G^o_{3} = 0 \ kJ/mol$

The Gibbs free energy of the reaction is mathematically represented as

$\Delta G^o_{re} = \sum \Delta G^o _p - \sum G^o _r$

$\Delta G^o_{re} = \sum \Delta G^o _1 - \sum( G^o _2 +G^o _3)$

Substituting values

From the balanced equation

$\Delta G^o_{re} =[ (2 * 0) + (\frac{3}{2} * 0 )] - [1 * - 8.80]$

$\Delta G^o_{re} = 8.80 kJ/mol =8800J/mol$

The Gibbs free energy of the reaction can also be represented mathematically as

$\Delta G^o_{re} = -RTln K$

Where R is the gas constant with a value of $R = 8.314 J/mol \cdot K$

T is the temperature with a given value of $T = 298 K$

K is the equilibrium constant

Now equilibrium constant for a reaction that contain gas is usually expressed in term of the partial pressure of the reactant and products that a gaseous in state

The equilibrium constant for this chemical reaction is mathematically represented as

$K_p =[ P_{O_2}]^{\frac{3}{2} }$

Where $[ P_{O_2}]$ is the equilibrium pressure of oxygen

The p subscript shows that we are obtaining the equilibrium constant using the partial pressure of gas in the reaction

Now equilibrium constant the subject on the second equation of the Gibbs free energy of the reaction

$K = e^{- \frac{\Delta G^o_{re}}{RT} }$

Substituting values

$K= e^{\frac{8800}{8.314 * 298} }$

$K =0.02867$

Now substituting this into the equation above to obtain the equilibrium of oxygen

$0.02867 = [P_{O_2}]^{[\frac{3}{2} ]}$

multiplying through by $1 ^{\frac{2}{3} }$

$P_{O_2} = [0.02867]^{\frac{2}{3} }$

$P_{O_2} = 0.09367\ atm$

3 0

3 years ago

Which of the following does not correctly describe Sn2 reactions of alkyl halides? A) The mechanism consists of a single step wi

Rashid [163]

Answer:

The correct answer is B the tertiary halides reacts faster than primary halides.

Explanation:

During SN2 reaction the nucleophile attack the alkyl halide from the opposite side resulting in the formation of transition state in which a bond is not completely broken or a new bond is not completely formed.

After a certain period of time the nucleophile attach with the substrate by substituting the existing nuclophile.

An increase in the bulkiness in the alkyl halide the SN2 reaction rate of that alkyl halide decreases.This phenomenon is called steric hindrance.

So from that point of view the that statement tertiary halides reacts faster that secondary halide is not correct.

7 0

3 years ago

The carbon-oxygen bond in CO has a higher bond dissociation enthalpy than a carbon-oxygen bond in CO2. Which is the best explana

kkurt [141]

Answer:

CO HAS A TRIPLE BOND WHILE C-O BOND IN CO2 IS A DOUBLE BOND

CO HAS A LONE PAIR ON CARBON WHILE CO2 DOES NOT

Explanation:

Bond dissociation bond enthalpy or energy is the energy needed to break 1 mole of a divalent molecule into separate atoms mostly in the gaseous state.

The carbon and oxygen in carbon monoxide form a triple bond as carbon monoxide has 10 electrons in their outermost shell which results into six shared electrons in 3 bonding orbitals as against the double bond formed by other carbon compounds. Four electrons come from oxygen and the remaining two from carbon and due to this, two electrons from oxygen will occupy one orbital and this forms a dative bond. Also because of the triple bond, carbon monoxide is often regarded as a more stable compound than carbon dioxide with a double bond. This gives it its higher bond dissociation enthalpy value and more energy is needed to break it into its separate atoms. This is in conjunction with a larger bond length similar to the bong length in a triple bond. This makes it more stronger than the bond dissociation enthalpy of carbon dioxide having a double bond.

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4 years ago