In an aquarium the water quantity is limited and fish excrete ammonia through their gills and body, this dissolves in water and creates toxins.
<u>Explanation</u>:
- In an aquarium the water quantity is limited and fish excrete ammonia through their gills and body, this dissolves in water and creates toxins. Over some time some bacteria develop in water which converts this ammonia into nitrites and then into nitrates. Till this process is complete, the aquarium remains a death trap.
There are some reasons for a fish to die early,
- This one is common for beginners. They don’t have any idea about the nitrogen cycle. And they simply buy a fish tank and fish on the same day, go home and set it up.
- Ammonia spikes - Even in a cycled tank, you can have occasional ammonia spikes due to overfeeding. Incompatible tank mates - If you put a too docile fish with a very aggressive cichlid, it will get harassed and eventually die due to stress.
Answer:It would never stop until something hit the ball, to slow it down.
Explanation:
This is so because there is no gravitational pull in space.
I believe that this atom is chlorine and the atom has an overall charge of zero.
Chlorine is chemical element which is atomic number 17 in the periodic table. Each chlorine atom has 17 protons (positively charged) in the nucleus balanced by 17 electrons (negatively charged) in the energy shells ( thus an overall charge of zero)
Answer:
67.1%
Explanation:
Based on the chemical equation, if we determine the moles of sodium carbonate, we can find the moles of NaHCO₃ that reacted and its mass, thus:
<em>Moles Na₂CO₃ - 105.99g/mol-:</em>
6.35g * (1mol / 105.99g) = 0.0599 moles of Na₂CO₃ are produced.
As 1 mole of sodium carbonate is produced when 2 moles of NaHCO₃ reacted, moles of NaHCO₃ that reacted are:
0.0599 moles of Na₂CO₃ * (2 moles NaHCO₃ / 1 mole Na₂CO₃) = 0.1198 moles of NaHCO₃
And the mass of NaHCO₃ in the sample (Molar mass: 84g/mol):
0.1198 moles of NaHCO₃ * (84g / mol) = 10.06g of NaHCO₃ were in the original sample.
And percent of NaHCO₃ in the sample is:
10.06g NaHCO₃ / 15g Sample * 100 =
<h3>67.1%</h3>
