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3 years ago

Simplify. (u^2 - 6u+7)+(-3u^2 + 2u +5)

Mathematics

1 answer:

Kobotan [32]3 years ago

5 0

Answer:

2u2−4u+12

Step-by-step explanation:

Conbine like terms:

=u2+−6u+7+−3u2+2u+5

=(u2+−3u2)+(−6u+2u)+(7+5)

=−2u2+−4u+12

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3 years ago

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3 years ago

Graph the line for y+1=−3/5(x−4) on the coordinate plane. Move Line Undo Redo Reset

dsp73

Answer:

The equation of line is shown below.

Step-by-step explanation:

The equation of line is

$y+1=\frac{-3}{5}(x-4)$

It is the point slope form of a line, therefore the slope of the line is $\frac{-3}{5}$ and the line passing through (4,-1).

Rewrite the above equation in slope intercept form.

$y=\frac{-3}{5}x+\frac{12}{5}-1$

$y=\frac{-3}{5}x+\frac{12-5}{5}$

$y=\frac{-3}{5}x+\frac{7}{5}$

The point slope form of a line is

$y=mx+b$

Where m is the slope and b is y-intercept.

Therefore the slope of the line is $\frac{-3}{5}$ and the y-intercept of the line is $\frac{7}{5}$ .

Slope is defined as

$m=\frac{Rise}{Run}$

Since the slope is negative, therefore the run of the line is considered on the left side. The line rise by 3 and run by 5, therefore we will add 7 in y and subtract 5 from x.

The y-intercept is $(0,\frac{7}{5})$ .

$(0-5,\frac{7}{5}+3)=(-5,\frac{22}{5})=(-5,4.4)$

Therefore we have three points (4,-1), (-5,4.4) and (0,1.4). Plot the point on the coordinate plane and connect them be a straight line.

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3 years ago