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Crank
3 years ago
10

Solve the equation for y 2x+6y=13

Mathematics
2 answers:
m_a_m_a [10]3 years ago
8 0
I hope this helps you



6y=13-2x


y=13-2x/6


y=13/6-1/3x
ivolga24 [154]3 years ago
8 0
So here is how we are going to solve for y for the given equation above:
2x+6y=13
Next, transfer 2x to the right side and it will look like this:
6y=13-2x
Now, divide both sides by 6, and it will look like this:
y=13-2x
    --------
       6
So, this is the final answer for y.
Hope this answers your question. Have a great day!
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21 students because if 6 represents 30% u add 6 two more time which equals 18 and 90% then u add 3 more because it is half of 6. when u add 3 more u will get 21 and 100%
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renu is 2 times older than suman. Anita is 9 years older than suman and 6 years younger than renu. jif some of their ages is 69,
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Answer:

suman is 15 and renu is 30 anita is 24

Step-by-step explanation:

15+30+24+69

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3 years ago
What is the slope-intercept form of the function described by this table?
Vikentia [17]
Y=5x - 3 Because the difference in the y values are 5, the rise is 5. That is the TOP of the slope. The difference in the x values is 1, that is the run or the BOTTOM of the slope. So m = 5/1. Using y = mx + b 2 = 5(1) + b -3 = b Therefore, y = 5x -3
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#20 four times the sum of number. and 15 is a least20. Let X represent the number. :find ball possible values for X
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6 0
3 years ago
Assume the sample below is a perfectly random sample of students at a school. How much greater is the mean of the
igor_vitrenko [27]

Answer:

0.75

Step-by-step explanation:

The table is not well presented (See Attachment)

There are at least two approaches to this question

Method 1:  

Steps

1. Calculate the mean of reported heights

Mean of reported heights = (61+68+57.5+48.5+75+65+80+68+69+63)/10

Mean of reported heights = 655/10

Mean of reported heights = 65.5

2. Calculate the mean of measured heights

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Mean of measured heights = 647.5/10

Mean of measured heights = 64.75

3. Get their difference

Difference = Mean of reported heights - Mean of measured heights

Difference = 65.5 - 64.75

Difference = 0,75

Method 2: Calculate the mean of their difference

Mean of difference = Sum of difference / Number of observations

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Mean of difference = 7.5/10

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Note that in both cases, the result is 0,75.

Hence, the reported heights at the school is 0.75 greater than the actual measured height

3 0
3 years ago
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