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cestrela7 [59]
3 years ago
10

And equation and solve a number increased by four and then doubled is the same as 28 decreased by three times the number find th

e number
Mathematics
1 answer:
Lelechka [254]3 years ago
7 0

Given:

A number increased by four and then doubled is the same as 28 decreased by three times the number.

To find:

The unknown number.

Solution:

Let the unknown number be x.

The number increased by four = x+4

And then doubled = 2(x + 4)

Three times the number = 3x

28 decreased by three times the number = 28 - 3x

Now,

2(x+4)=28-3x

2x+8=28-3x

Isolate variable terms.

2x+3x=28-8

5x=20

Divide both sides by 5.

x=\dfrac{20}{5}

x=4

Therefore, the value of unknown number is 4.

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Please help D: Given f (x) = 3 x minus 1 and g (x) = 2 x minus 3, for which value of x does g (x) = f (2)?
AfilCa [17]
<h3>Answer:   D.  x = 4</h3>

===============================================

Explanation:

First compute f(2)

f(x) = 3x-1

f(2) = 3(2) - 1 ... replace every x with 2; use PEMDAS to simplify

f(2) = 6 - 1

f(2) = 5

When we say g(x) = f(2), we really mean g(x) = 5

g(x) = 2x-3

2x-3 = g(x)

2x-3 = 5 .... plug in g(x) = 5

2x-3+3 = 5+3 ... add 3 to both sides

2x = 8

2x/2 = 8/2 ... dividing both sides by 2

x = 4

8 0
4 years ago
Im learning about Recursive and Explicit in Pre-Calc, and it says to use the rule to write the first three terms of each sequenc
Tems11 [23]

Hello,

4. you have sequences defined by the first term and a recursive relation.

a_1=3\\\\a_n=2a_{n-1} \ \ \text{ for n}> 1

Take n = 2, it gives

a_2=2a_1 , right?

But you know a_1=3

so a_2=2a_1=2*3=6

This is the second term. You are asked to find the first three terms.

Now, let's take n = 3

a_3=2a_2=2*6=12

So the first three terms are 3, 6, 12.

6.

a_1=12\\\\a_2=\dfrac{1}{2}a_1+1=\dfrac{12}{2}+1=6+1=7 \\ \\a_3=\dfrac{1}{2}a_2+1=\dfrac{7}{2}+1=\dfrac{9}{2}

8.

a_1=10\\ \\a_2=-3a_1=-3*10=-30\\\\a_3=-3a_2=-3*(-30)=90

10.

a_1=2\\\\a_2=-1\\\\a_3=a_2+a_1=-1+2=1\\\\a_4=a_3+a_2=1-1=0

Do not hesitate if you have any question.

Thank you

8 0
4 years ago
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