This problem fits the conditional probability formula very well. The formula is P(B|A) = P(B ∩ A)/P(A). If event A is winning the first game, and event B is winning the second, then P(B ∩ A) = 0.44, and P(A) = 0.6. So P(B|A) is obtained by dividing 0.44 by 0.6, which is about 0.733.
Horizontal translation by h to the right (h>=0) is given by
g(x)=f(x-h)
For translation to the left, we have h=-3
g(x)=f(x-(h)) =f(x-(-3))=f(x+3)
The total mass of the order is
.. 4*(.700 kg) +8*(.725 kg) +3*(.600 kg) +5*(.675 kg) = 13.775 kg
.. 13.755/4 ≈ 3.44, so a minimum of 4 boxes will be required.
The pies can be packed 5 to a box in any combination.
The order will require 4 boxes
Answer:
The test statistic is and the observed value 1.68
Step-by-step explanation:
We have a large sample size n = 100, the point estimate for the true proportion of overfilled bags p is given by . The test statistic is given by which is distributed as a standard normal variable approximately because we have a large sample. The observed value for the test statistic in this case is
The correct answer is C) 40-4x-12x^2