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docker41 [41]
2 years ago
5

What would be the solution for x inequality 47-4x<7

Mathematics
2 answers:
sladkih [1.3K]2 years ago
7 0

Answer:

x > 10

Step-by-step explanation:

Given

47 - 4x < 7 ( subtract 47 from both sides )

- 4x  < - 40

Divide both sides by - 4, reversing the symbol as a result of dividing by a negative quantity.

x > 10

Viefleur [7K]2 years ago
4 0

Answer:

x>10

Step-by-step explanation:

Think of this as an equation:

47-4x<7

Add 4x to both sides:

47<7+4x

Subtract 7 from both sides:

40<4x

Divide both sides by 4:

x>10

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3(-0.4n-0.7)=-3.2n-2.58
svlad2 [7]

Answer:

n=-0.24

Step-by-step explanation:

3\left(-0.4n-0.7\right)=-3.2n-2.58

Use distributive property.

-1.2n-2.1=-3.2n-2.58

-1.2n-2.1+2.1=-3.2n-2.58+2.1

-1.2n=-3.2n-0.48

-1.2n+3.2n=-3.2n-0.48+3.2n

2n=-0.48

\frac{2n}{2}=\frac{-0.48}{2}

n=-0.24

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3 years ago
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The weight would be 10 pounds
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Step-by-step explanation:

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3 years ago
Prove that sin²∅+cos²∅=1 ?​
sasho [114]

Step-by-step explanation:

Let ABC be a right angled triangle where there's a right angle in B . Let the measure of the angle BAC be ∅. So,

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Also,

\cos(∅)  =  \frac{AB}{AC}

=  >  { \cos}^{2}∅ =  \frac{ {AB}^{2} }{ {AC}^{2} }

Now adding the values of sin^2∅& cos^2∅,

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=  >  { \sin}^{2} ∅ +  { \cos}^{2} ∅ =  \frac{ {AB}^{2} +  {BC}^{2}  }{ {AC}^{2} }

But we know that

{AC}^{2}  =  {AB}^{2}   +  {BC}^{2} by applying Pythagorean Theorem

So ,

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