When multiplying fractions just multiply the numerator and denominators together, then simplify the fraction you get.
To solve the addition problem, first convert 2 and 1/2 to an improper fraction. It should be 5/2. Now 3/8 and 5/2 must be added together.
To add these, they must have the same denominator. Let's give 5/2 a denominator of 8, so it matches 3/8.
To give 5/2 a denominator of 8, you are starting with a denominator of 2. 2 × 4 = 8, so you must multiply 5/2 by 4.
You should get 20/8. Now you have to add 20/8 and 3/8. The only thing you add is the numerator, so you should get 23/8 as a final answer.
For the subtraction problem, do these same steps to make the fractions you must subtract have the same denominator, then subtract only the numerator to get the answer. Once you solve the subtraction problem, text me what you got so I can check it for you. :)
So if we see the first one (8,4) x=8 and y=4
And we see the 2nd one (4,y) x=4 and y=?
We notice that the value of x its been halved. So y varies with x so y value also has to be halved so y= 2
This is always ''interesting'' If you see an absolute value, you always need to deal with when it is zero:
(x-4)=0 ===> x=4,
so that now you have to plot 2 functions!
For x<= 4: what's inside the absolute value (x-4) is negative, right?, then let's make it +, by multiplying by -1:
|x-4| = -(x-4)=4-x
Then:
for x<=4, y = -x+4-7 = -x-3
for x=>4, (x-4) is positive, so no changes:
y= x-4-7 = x-11,
Now plot both lines. Pick up some x that are 4 or less, for y = -x-3, and some points that are 4 or greater, for y=x-11
In fact, only two points are necessary to draw a line, right? So if you want to go full speed, choose:
x=4 and x= 3 for y=-x-3
And just x=5 for y=x-11
The reason is that the absolute value is continuous, so x=4 works for both:
x=4===> y=-4-3 = -7
x==4 ====> y = 4-11=-7!
abs() usually have a cusp int he point where it is =0
Hope it helps, despite being this long!
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Answer:
- one: x+3 = 2x
- none: x+3 = x
- infinite: x+3 = x+3
Step-by-step explanation:
A linear equation with variable terms on opposite sides of the equal sign will have one solution when the coefficients of those variables are different.
x+3 = 2x . . . . has one solution (x=3)
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There will be no solution if the variable terms on opposite sides of the equal sign have the same coefficient, but the constants are different. Such an equation can be reduced to 0 = 1, which cannot be made true by any value of the variable.
x +3 = x . . . . has no solutions
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There will be an infinite number of solutions if the left side of the equal sign is the same as the right side. Every value of the variable will satisfy the equation.
x +3 = x +3 . . . . has infinite solutions
The answer is 891. 99 is the greatest 2 digit number and 9 is the greatest 1 digit number. So the product of the two (multiply them) gives you your answer of 891 (99 x 9 = 891).
