It sounds like you are setting up the equation below.
(2/5)P = 30
To solve this equation for P, you would multiply both sides of the equation by 5/2.
Three hundred thirty seven thousand, one hundred seventy three
Answer:
0.13591.
Step-by-step explanation:
We re asked to find the probability of randomly selecting a score between 1 and 2 standard deviations below the mean.
We know that z-score tells us that a data point is how many standard deviation above or below mean.
To solve our given problem, we need to find area between z-score of -2 and -1 that is
.
We will use formula
to solve our given problem.

Using normal distribution table, we will get:


Therefore, the probability of randomly selecting a score between 1 and 2 standard deviations below the mean would be 0.13591.
1200 * 0.05 * 4 = 240$ the amount of interest after 4 years.
total 1200+240=1440$