Answer:
Yes, Mina is correct
Step-by-step explanation:
Let the triangles be A and B
Given
Triangle A:
Triangle B:
Required
Is Mina's claim correct?
First, we calculate the third angle in both triangles.
For A:
For B:
For triangle A, the angles are: 34, 57 and 89
For triangle B, the angles are: 34, 57 and 89
<em>Since both triangles have the same angles, then by the postulate of AAA (Angle-Angle-Angle), the triangles are similar.</em>
∠ACB is an inscribed angle, so
m∠ACB= (1/2)mAB =(1/2)*50=25⁰
m∠ACB= 25⁰
Answer:
34% decrease
Step-by-step explanation:
(V1-V2)/V1x100
450-297=153
153/450=0.34
0.34 x 100=34
34% decrease
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Answer:
(0.5, 1.3)(0.5, 1.3)
Step-by-step explanation:
Given equations are:
As we can see that the given equations are linear equations which are graphed as straight lines on graph. The solution of two equations is the point of their intersection on the graph.
We can plot the graph of both equations using any online or desktop graphing tool.
We have used "Desmos" online graphing calculator to plot the graph of two lines (Picture Attached)
We can see from the graph that the lines intersect at: (0.517, 1.267)
Rounding off both coordinates of point of intersection to nearest tenth we get
(0.5, 1.3)
Hence,
(0.5, 1.3) is the correct answer
Keywords: Linear equations, variables
"Product" means we are looking at a multiplication problem.
Can be written as:
A number (n) times 50
n x 50
The simplest (and most common way) to write it:
50n
