9514 1404 393
Answer:
(W, T, L, S) = (3, 2, 1, 4.1)
Step-by-step explanation:
For some number of wins (W), ties (T), and losses (L), the player's score will be ...
score = 2.2W +0.25T -3L
For 3 wins, 2 ties, and 1 loss, the player's score is ...
2.2(3) +0.25(2) -3(1) = 6.6 +0.5 -3 = 4.1
Answer:
p ∈ IR - {6}
Step-by-step explanation:
The set of all linear combination of two vectors ''u'' and ''v'' that belong to R2
is all R2 ⇔
And also u and v must be linearly independent.
In order to achieve the final condition, we can make a matrix that belongs to 
using the vectors ''u'' and ''v'' to form its columns, and next calculate the determinant. Finally, we will need that this determinant must be different to zero.
Let's make the matrix :
![A=\left[\begin{array}{cc}3&1&p&2\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%261%26p%262%5Cend%7Barray%7D%5Cright%5D)
We used the first vector ''u'' as the first column of the matrix A
We used the second vector ''v'' as the second column of the matrix A
The determinant of the matrix ''A'' is
We need this determinant to be different to zero
The only restriction in order to the set of all linear combination of ''u'' and ''v'' to be R2 is that
We can write : p ∈ IR - {6}
Notice that is 
⇒
If we write 
, the vectors ''u'' and ''v'' wouldn't be linearly independent and therefore the set of all linear combination of ''u'' and ''b'' wouldn't be R2.
Answer:
a. 13/3
b. 3 3/4
d. 1 7/8
c. 7/2
Step-by-step explanation:
a. 4 1/3 given
4*3=12 multiply the whole numbers with the denominator
12+1 =13 add the numerator to the product
13/3 put sum over denominator
b. 15/4 given
15/4=3 with a remainder of 3 divide numerator by denominator
3 3/4 rewrite as mixed number
d. 15/8 given
15/8=1 with a remainder of 7 divide numerator by denominator
1 7/8 rewrite as mixed number
c. 3 1/2 given
3*2=6 multiply whole number by denominator
6+1=7 add numerator to product
7/2 put sum over denominator
To find the volume of the box you have to do the formula for volume
the formula for volume is lxwxh aka length x width x height
so first you have to do 3/4 x 1/2
3/4 x 1/2 = 3/8
Next, you have to do 3/8 x 1/4
3/8 x 1/4 = 3/32
so the volume of the box is 3/32
HOPE THIS HELPS!!!
