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HACTEHA [7]
3 years ago
8

Find the area of this parallelogram.

Mathematics
1 answer:
Grace [21]3 years ago
3 0
Answer: A
i hope it helped
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What is the period of the function f(x) shown in the graph?
Dahasolnce [82]

Answer: The answer is pi

7 0
3 years ago
Which equation represents a line which is parallel to the line y=3x–8
Lena [83]

Answer:

The equation of line which is parallel to the given line is y =  3 x + k.

Step-by-step explanation:

The equation of the line is

y = 3 x - 8

Compare with the standard equation

y = mx + c

The slope of line is

m = 3

So, the line parallel to the given line is

y = 3 x + k

where, k is any real number.

3 0
3 years ago
Which equation shows a valid, practical step in solving
lesantik [10]

For this case we have the following equation:

\sqrt [4] {2x-8} + \sqrt [4] {2x + 8} = 0

If we subtract both sides of the equation \sqrt [4] {2x + 8} we have:

\sqrt [4] {2x-8} = - \sqrt [4] {2x + 8}

To eliminate the radical we raise both sides of the equation to the fourth power:

(\sqrt [4] {2x-8}) ^ 4 = (- \sqrt [4] {2x + 8}) ^ 4

Answer:

Option D

6 0
4 years ago
What is the answer??​
vredina [299]

Answer:

The answer is what it is.

Step-by-step explanation:

7 0
4 years ago
Find the distance between these points. C(0, 4), T(-6, -3) √(37) √(109) √(85)
finlep [7]

Answer:

The answer is

<h2>\sqrt{85}</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

<h3>d =  \sqrt{( {x1 - x2})^{2}  +  ({y1 - y2})^{2} }  \\</h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

C(0, 4), T(-6, -3)

The distance between them is

<h3>|CT|  =  \sqrt{ ({0 + 6})^{2}  +  ({4 + 3})^{2} }  \\  =  \sqrt{ {6}^{2} +  {7}^{2}  }  \\  =  \sqrt{36 + 49}</h3>

We have the final answer as

<h3>\sqrt{85}</h3>

Hope this helps you

6 0
3 years ago
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