Answer:
The equation of line which is parallel to the given line is y = 3 x + k.
Step-by-step explanation:
The equation of the line is
y = 3 x - 8
Compare with the standard equation
y = mx + c
The slope of line is
m = 3
So, the line parallel to the given line is
y = 3 x + k
where, k is any real number.
For this case we have the following equation:
![\sqrt [4] {2x-8} + \sqrt [4] {2x + 8} = 0](https://tex.z-dn.net/?f=%5Csqrt%20%5B4%5D%20%7B2x-8%7D%20%2B%20%5Csqrt%20%5B4%5D%20%7B2x%20%2B%208%7D%20%3D%200)
If we subtract both sides of the equation
we have:
![\sqrt [4] {2x-8} = - \sqrt [4] {2x + 8}](https://tex.z-dn.net/?f=%5Csqrt%20%5B4%5D%20%7B2x-8%7D%20%3D%20-%20%5Csqrt%20%5B4%5D%20%7B2x%20%2B%208%7D)
To eliminate the radical we raise both sides of the equation to the fourth power:
![(\sqrt [4] {2x-8}) ^ 4 = (- \sqrt [4] {2x + 8}) ^ 4](https://tex.z-dn.net/?f=%28%5Csqrt%20%5B4%5D%20%7B2x-8%7D%29%20%5E%204%20%3D%20%28-%20%5Csqrt%20%5B4%5D%20%7B2x%20%2B%208%7D%29%20%5E%204)
Answer:
Option D
Answer:
The answer is what it is.
Step-by-step explanation:
Answer:
The answer is
<h2>

</h2>
Step-by-step explanation:
The distance between two points can be found by using the formula
<h3>

</h3>
where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
C(0, 4), T(-6, -3)
The distance between them is
<h3>

</h3>
We have the final answer as
<h3>

</h3>
Hope this helps you