Answer:
Find the complete table in attached file.
Step-by-step explanation:
Find the Incomplete table in attached file
Given:
A car travels 55 miles per hour for 2 hours.
So the speed of the car 55 miles per hour is constant for 2 hours.
Using speed formula.

Second row.
From the second row of the table
and speed is constant
, so we need to find only distance.




Third row.
From the third row of the table
and speed is constant
, so we need to find only distance.




Fourth row.
From the fourth row of the table
and speed is constant
, so we need to find time.




Therefore we complete the table from the above calculation.
The answer is 7.75. Since there can not be 7.75 days, you can round that to 8 and say that it's almost 8 days. Hope this helps!
Answer:
-4
+3
12
-0.5, 12.25
x = -0.5
Step-by-step explanation:
The x intercepts are the values of x when y = 0 ie the roots of the equation

or

We can re-write the above as:
(x+4) (x-3) = 0
This gives the two roots as x = -4 and x = +3. Leftmost (smallest) root is -4 and rightmost(largest) root is +3
y intercept is when x = 0. Plugging into the original equation, y value at x = 0 is 12
Vertex x value is given by the formula -b/2a where a is the coefficient of x^2 and b the coefficient of x
Here a = -1, b= -1 so vertex x value = - (-1)/(-1).2 = - 1/2 = -0.5
Plugging this value of x into the original function gives the vertex y value

The line of symmetry is the vertical line corresponding to the vertex x value so line of symmetry is at x = -0.5
The graph of the quadratic function shows these values
Answer:
Perimeter square = 8 sqrt(pi)
Step-by-step explanation:
The perimeter of a square is 4*s
The area of a circle is Area = pi * r^2
The circumference of a circle is C = 2*pi * r
C = 4 pi
4pi = 2*pi * r
r = 2
So the area of the circle is pi * r^2 = pi * 2^2 = 4pi
The square has the same area
Area = 4*pi
Square = 4*pi
s^2 = 4*pi
s = sqrt(4*pi)
s = 2*sqrt(pi)
The perimeter = 4 * 2 * sqrt(pi)
The perimeter = 8 * sqrt(pi)