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IRINA_888 [86]
3 years ago
7

Find the perimeter of the polygon if angle B is congruent to angle D.

Mathematics
1 answer:
UkoKoshka [18]3 years ago
8 0

Answer:

32

Step-by-step explanation:

The sides of the quadrilateral are tangents to the circle.

Tangents drawn from an external point to the circle are congruent

5+5+4+4+3+3+4+4=32

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Mhanifa please help this is due soon
kvv77 [185]

Answer:

<u>Use Pythagorean theorem:</u>

  • a² + b² = c²

#7

  • 3² + 7² = 9 + 49 = 58
  • (√57)² = 57
  • 58 ≠ 57
  • No

#8

  • 11² + 2² = 121 + 4 = 125
  • (5√5)² = 25*5 = 125
  • 125 = 125
  • Yes
3 0
3 years ago
Describe the pattern in the sequence. Find the next two terms of the difference -2, -5,-8, -11
PSYCHO15rus [73]

Hello from MrBillDoesMath!

Answer:

"-3" is added to a sequence member to get the next number. This next two terms are -14 and  -17


Discussion:

Note that -2 -3 = -5 and

                -5 -3 = -8 and

                -8 - 3 = -11


"-3" is added to a sequence member to get the next number. This implies that the next two terms are -11 -3 = -14 and -14 -3 = -17

Regards,  

MrB


5 0
3 years ago
Brian can type 1 and one-third pages every 20 minutes. How many pages can he type in 2.5 hours? 7.5 pages 10 pages 22.5 pages 20
vladimir2022 [97]

Answer:

10 pages

Step-by-step explanation:

1 and 1/3 pages multiplies by 7.5 brings us to the answer of ten pages

20 minutes goes into 2 and 1/2 hours 7.5 times

5 0
3 years ago
Read 2 more answers
4000(1 + 0.025/52) 52•15=<br> Round answer to the nearest hundredth
Sauron [17]
Use PEMDAS to solve this so

4000(1.0005) 52 • 15 =
4002 (52) • 15 = 3,121,500
4 0
3 years ago
A consumer organization inspecting new cars found that many had appearance defects (dents, scratches, paint chips, etc.). While
Murljashka [212]

Answer:

The expected number of appearance defects in a new car  = 0.64

standard deviation = 0.93(approximately)

Step-by-step explanation:

Given -

7% had exactly three, 11% exactly two, and 21% only one defect in cars.

Let X be no of defects in a car

P(X=3) = .07 , P(X=2) = .11 , P(X=3) = .21

P(X=0 ) = 1 - .07 - .11 - .21 = 0.61

The expected number of appearance defects in a new car =

E(X) = \nu = = \sum X P(X) =3\times 0.07 + 2\times0.11 + 3\times0.21 + 0\times0.61 = 0.64

\sigma^{2}  = variation of E(X) = \sum (X - \nu) ^{2}P(X) = (3 - 0.64) ^{2}\times0.07 + (2 - 0.64) ^{2}\times0.11 + (1 - 0.64) ^{2}\times0.21 + (0 - 0.64) ^{2}\times0.61

 = (2.36) ^{2}\times0.07 + (1.36) ^{2}\times0.11 + (.36) ^{2}\times0.21 + ( 0.64) ^{2}\times0.61 = 0.8704

standard deviation  =  \sqrt{\sigma^{2}} = \sqrt{0.8704^{2}} = 0.93(approximately)

4 0
3 years ago
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