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2 years ago

2/3 - 2/9 what is the answer ???

Mathematics

2 answers:

riadik2000 [5.3K]2 years ago

8 0

Answer:

0.44

Step-by-step explanation:

2/3 - 2/9 = 0.44

neonofarm [45]2 years ago

7 0

Answer: 4/9

Step-by-step explanation:

Covert them into having the same denominator so 2/3 into 6/9 then subtract 6/9 -2/9. 6-2 is 4 and you keep the denominator the same which makes the answer 4/9.

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How do you do this I don’t get it

Ierofanga [76]

Answer:

x= 65 z= 38 y= 77

Step-by-step explanation:

x=65° (opposite angles are equal)

z= 180°-[71+71 (bc the other side is also equal to 71)]

z= 180°-142°=38°

y= 180 - [sum of angle x (65°) and angle z (38°)]

y= 180 - 103= 77°

to make sure ur answer is correct the sum of angle x, y and z MUST = 180

lets check:

65° + 38° + 77° = 180°

6 0

3 years ago

A sports club needs to raise at least $500 by selling chocolate bars for $2.50 each. Sebastian wants to know how many chocolate

Nataly [62]

Answer

they would need to sell 200 chocolate bars

Step-by-step explanation:

500 divided by 2.50 = 200

2 x 200 = 400

.50 x 200 = 100

400 + 100 = 500

6 0

3 years ago

Read 2 more answers

Find the mass and center of mass of the lamina that occupies the region D and has the given density function rho. D is the trian

Alla [95]

Answer: mass (m) = 4 kg

center of mass coordinate: (15.75,4.5)

Step-by-step explanation: As a surface, a lamina has 2 dimensions (x,y) and a density function.

The region D is shown in the attachment.

From the image of the triangle, lamina is limited at x-axis: 0≤x≤2

At y-axis, it is limited by the lines formed between (0,0) and (2,1) and (2,1) and (0.3):

Points (0,0) and (2,1):

y = $\frac{1-0}{2-0}(x-0)$

y = $\frac{x}{2}$

Points (2,1) and (0,3):

y = $\frac{3-1}{0-2}(x-0) + 3$

y = -x + 3

Now, find total mass, which is given by the formula:

$m = \int\limits^a_b {\int\limits^a_b {\rho(x,y)} \, dA }$

Calculating for the limits above:

$m = \int\limits^2_0 {\int\limits^a_\frac{x}{2} {2(x+y)} \, dy \, dx }$

where a = -x+3

$m = 2.\int\limits^2_0 {\int\limits^a_\frac{x}{2} {(xy+\frac{y^{2}}{2} )} \, dx }$

$m = 2.\int\limits^2_0 {(-x^{2}-\frac{x^{2}}{2}+3x )} \, dx }$

$m = 2.\int\limits^2_0 {(\frac{-3x^{2}}{2}+3x)} \, dx }$

$m = 2.(\frac{-3.2^{2}}{2}+3.2-0)$

m = 2(-4+6)

m = 4

Mass of the lamina that occupies region D is 4.

Center of mass is the point of gravity of an object if it is in an uniform gravitational field. For the lamina, or any other 2 dimensional object, center of mass is calculated by:

$M_{x} = \int\limits^a_b {\int\limits^a_b {y.\rho(x,y)} \, dA }$

$M_{y} = \int\limits^a_b {\int\limits^a_b {x.\rho(x,y)} \, dA }$

$M_{x}$ and $M_{y}$ are moments of the lamina about x-axis and y-axis, respectively.

Calculating moments:

For moment about x-axis:

$M_{x} = \int\limits^a_b {\int\limits^a_b {y.\rho(x,y)} \, dA }$

$M_{x} = \int\limits^2_0 {\int\limits^a_\frac{x}{2} {2.y.(x+y)} \, dy\, dx }$

$M_{x} = 2\int\limits^2_0 {\int\limits^a_\frac{x}{2} {y.x+y^{2}} \, dy\, dx }$

$M_{x} = 2\int\limits^2_0 { ({\frac{y^{2}x}{2}+\frac{y^{3}}{3})}\, dx }$

$M_{x} = 2\int\limits^2_0 { ({\frac{x(-x+3)^{2}}{2}+\frac{(-x+3)^{3}}{3} -\frac{x^{3}}{8}-\frac{x^{3}}{24} )}\, dx }$

$M_{x} = 2.(\frac{-9.x^{2}}{4}+9x)$

$M_{x} = 2.(\frac{-9.2^{2}}{4}+9.2)$

$M_{x} = 18$

Now to find the x-coordinate:

x = $\frac{M_{y}}{m}$

x = $\frac{63}{4}$

x = 15.75

For moment about the y-axis:

$M_{y} = \int\limits^2_0 {\int\limits^a_\frac{x}{2} {2x.(x+y))} \, dy\,dx }$

$M_{y} = 2.\int\limits^2_0 {\int\limits^a_\frac{x}{2} {x^{2}+yx} \, dy\,dx }$

$M_{y} = 2.\int\limits^2_0 {y.x^{2}+x.{\frac{y^{2}}{2} } } \,dx }$

$M_{y} = 2.\int\limits^2_0 {x^{2}.(-x+3)+\frac{x.(-x+3)^{2}}{2} - {\frac{x^{3}}{2}-\frac{x^{3}}{8} } } \,dx }$

$M_{y} = 2.\int\limits^2_0 {\frac{-9x^3}{8}+\frac{9x}{2} } \,dx }$

$M_{y} = 2.({\frac{-9x^4}{32}+9x^{2})$

$M_{y} = 2.({\frac{-9.2^4}{32}+9.2^{2}-0)$

$M{y} =$ 63

To find y-coordinate:

y = $\frac{M_{x}}{m}$

y = $\frac{18}{4}$

y = 4.5

Center mass coordinates for the lamina are (15.75,4.5)

3 0

3 years ago

Use the graph to write a linear function that relates y to x .

sergiy2304 [10]

Answer:

2y = x + 2

Step-by-step explanation:

Looking at the graph, we can see from one point to the next (from right to left), the x-value rises by 2 and the y-value by 1;

From this we can work out the gradient between two points using the formula, i.e. the change/difference in y divided by the change/difference in x:

$m = \frac{dy}{dx} = \frac{1}{2}$

Joining the points gives a straight line, which means a constant gradient of ¹/₂

Use the line equation formula to get the function:

y - y₁ = m(x - x₁)

m = ¹/₂

x₁ = 0

y₁ = 1

y - 1 = ¹/₂.(x - 0)

y - 1 = ¹/₂.x

2y - 2 = x

2y = x + 2

8 0

3 years ago

Write a literal corresponding to the floating point value one-and-a-half.

kotykmax [81]

1.5 In C or C++, a floating point literal is nothing more than a sequence of decimal digits with either or both an decimal point, or an exponent with optionally a type specifier. The value could be any of the following: 1.5, 1.5e0, 0.15e1, 15e-1, etc.

7 0

3 years ago