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antiseptic1488 [7]
3 years ago
9

Can you show me how to reduce 99/143?

Mathematics
2 answers:
Rudiy273 years ago
6 0
To reduce a fraction fully, divide the denominator and numerator by their greatest common factor.

Factors of 99: 1, 3, 9, 11, 33, 99
Factors of 143: 1, 11, 13, 143
Common Factors: 1, 11
Great Common Factor: 11

\frac{99}{11}=9 \\  \\  \frac{143}{11}=13   \\  \\  \frac{99}{143} = \frac{9}{13}
kodGreya [7K]3 years ago
4 0
99|3\\33|3\\11|11\\.\ 1|\\99=3\times3\times\fbox{11}\\\\143|11\\.\ 13|13\\.\ \ 1|\\143=\fbox{11}\times13\\\\therefore:\frac{99}{143}=\frac{3\times3\times\fbox{11}}{13\times\fbox{11}}=\frac{3\times3}{13}=\boxed{\boxed{\frac{9}{13}}}
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3 years ago
Which quadratic equation has solutions x=8 and x=−1?
andrezito [222]
There are two ways you can do this

Using the formula


{x}^{2}  - (sum \: of \: roots)x + poduct \: of \: roots = 0

{x}^{2}  - (8+-1)x +  - 1 \times 8 = 0


{x}^{2}  - 7x  - 8 = 0


Working backwards


x = 8 \: or \: x =  - 1
\Rightarrow x-8=0  \: or  \: x+1=0

\Rightarrow (x-8)(x + 1)=0
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7 0
3 years ago
How to show these 2 problems are inverses
nataly862011 [7]
\bf \begin{cases}
f(x)=\sqrt[3]{7x-2}\\\\
g(x)=\cfrac{x^3+2}{7}
\end{cases}\\\\
-----------------------------\\\\
now
\\\\
f[\ g(x)\ ]\implies f\left[ \frac{x^3+2}{7} \right]\implies \sqrt[3]{7\left[ \frac{x^3+2}{7} \right]-2}\implies \sqrt[3]{x^3+2-2}
\\\\\\
\sqrt[3]{x^3}\implies x\\\\
-----------------------------\\\\
or
\\\\
g[\ f(x)\ ]\implies g\left[\sqrt[3]{7x-2}\right]\implies \cfrac{\left[\sqrt[3]{7x-2}\right]^3+2}{7}
\\\\\\
\cfrac{7x-2+2}{7}\implies \cfrac{7x}{7}\implies x

thus f[ g(x) ] = x indeed, or g[ f(x) ] =x, thus they're indeed inverse of each other
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3 years ago
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