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antiseptic1488 [7]
3 years ago
9

Can you show me how to reduce 99/143?

Mathematics
2 answers:
Rudiy273 years ago
6 0
To reduce a fraction fully, divide the denominator and numerator by their greatest common factor.

Factors of 99: 1, 3, 9, 11, 33, 99
Factors of 143: 1, 11, 13, 143
Common Factors: 1, 11
Great Common Factor: 11

\frac{99}{11}=9 \\  \\  \frac{143}{11}=13   \\  \\  \frac{99}{143} = \frac{9}{13}
kodGreya [7K]3 years ago
4 0
99|3\\33|3\\11|11\\.\ 1|\\99=3\times3\times\fbox{11}\\\\143|11\\.\ 13|13\\.\ \ 1|\\143=\fbox{11}\times13\\\\therefore:\frac{99}{143}=\frac{3\times3\times\fbox{11}}{13\times\fbox{11}}=\frac{3\times3}{13}=\boxed{\boxed{\frac{9}{13}}}
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Consider the probabilities of people taking pregnancy tests. Assume that the true probability of pregnancy for all people who ta
Valentin [98]

Using conditional probability, it is found that there is a 0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

<h3>What is Conditional Probability?</h3>

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem, the events are:

  • Event A: Positive test result.
  • Event B: Pregnant.

The probability of a positive test result is composed by:

  • 99% of 10%(truly pregnant).
  • 2% of 90%(not pregnant).

Hence:

P(A) = 0.99(0.1) + 0.02(0.9) = 0.117

The probability of both a positive test result and pregnancy is:

P(A \cap B) = 0.99(0.1)

Hence, the conditional probability is:

P(B|A) = \frac{0.99(0.1)}{0.117} = 0.8462

0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

You can learn more about conditional probability at brainly.com/question/14398287

7 0
2 years ago
Given the Venn Diagram what is the probability that a person is an only child OR only has sisters?
Svetradugi [14.3K]

Based on the venn diagram of siblings, the probability of being an only child or having only sisters is d. 0.50.

<h3>What is probability of being an only child or having a sister?</h3>

The probability of being an only child or having a sister can be found as:

= (Number of those only sister + Number of only children) / Total number of people in poll

Solving gives:

= (8 + 7) / (8 + 10 + 5 + 7)

= 15 / 30

= 0.50

In conclusion, the probability of having a brother and sister is 0.50.

Find out more on Venn diagrams at brainly.com/question/9085273

#SPJ1

7 0
2 years ago
Y= 12 - 4.5x what’s the slope
mestny [16]
What you do is move the equation around so the 12 -4.5x would now turn into y=-4.5x+12
6 0
4 years ago
The sum of three consecutive terms in an arithmetic sequence is 27, and their product is 585. find the three terms.
sammy [17]
\text{the three consecutive terms in an arithmetic sequence}\\a;\ a+d;\ a+2d\\\\\text{system of equals}\\\\ \left\{\begin{array}{ccc}a+a+d+a+2d=27\\a(a+d)(a+2d)=585\end{array}\right\\ \left\{\begin{array}{ccc}3a+3d=27&|:3\\a(a+d)(a+2d)=585\end{array}\right\\ \left\{\begin{array}{ccc}a+d=9&\to d=9-a\\a(a+d)(a+2d)=585\end{array}\right\\
\text{substitute to the second equation}\\\\a(a+9-a)(a+2(9-a))=585\\\\a(9)(a+18-2a)=585\\9a(18-a)=585\ \ \ |:9\\a(18-a)=65\\18a-a^2=65\ \ \ |\text{change the signs}\\a^2-18a=-65\\a^2-2a\cdot9=-65\ \ \ |+9^2\\\underbrace{a^2-2a\cdot9+9^2}_{(a-b)^2=a^2-2ab+b^2}=-65+9^2\\(a-9)^2=16\to a-9\pm\sqrt{16}\\a-9=-4\ \vee\ a-9=4\ \ \ |+9\\a=5\ \vee\ a=13\\\\d=9-5=4\ \vee\ d=9-13=-4
Answer:\ a=5;\ a+d=9; a+2d=13\ vee\ a=13;\ a+d=9;\ a+2d=5

5 0
3 years ago
F is directly proportional to a. If F=36 when a=9 , find F when a=4
kicyunya [14]

Step-by-step explanation:

f=ka

36=9k

k=4

f=4×4

f=16

8 0
2 years ago
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