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natka813 [3]
3 years ago
7

Given the midpoint and one endpoint of a line segment, find the other endpoint.

Mathematics
1 answer:
neonofarm [45]3 years ago
3 0

Answer:

(-12 , 2)

Step-by-step explanation:

<u>GIVEN :-</u>

  • Co-ordinates of one endpoint = (-4 , -10)
  • Co-ordinates of the midpoint = (-8 , -4)

<u>TO FIND :-</u>

  • Co-ordinates of another endpoint.

<u>FACTS TO KNOW BEFORE SOLVING :-</u>

<em><u>Section Formula :-</u></em>

Let AB  be a line segment where co-ordinates of A = (x¹ , y¹) and co-ordinates of B = (x² , y²). Let P be the midpoint of AB . So , by using section formula , the co-ordinates of P =

(x , y) = (\frac{x^2 + x^1}{2} ,\frac{y^2 + y^1}{2} )

<u>PROCEDURE :-</u>

Let the co-ordinates of another endpoint be (x , y)

So ,

(-8 , -4) = (\frac{-4 + x}{2} , \frac{-10 + y}{2} )

First , lets solve for x.

=> \frac{x - 4}{2} = -8

=> x - 4 = -8 \times 2 = -16

=> x = -16 + 4 = -12

Now , lets solve for y.

=> \frac{y - 10}{2} = -4

=> y - 10 = -4 \times 2 = -8

=> y = -8 + 10 = 2

∴ The co-ordinates of another endpoint = (-12 , 2)

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-2

Step-by-step explanation:

the rate of change or slope (M) is -2

Hope this helps:P

6 0
2 years ago
1. Solve the equation.<br>4(x + 5) = 24<br><br>​
bixtya [17]

Answer:

x=1

Step-by-step explanation:

4(x+5)= 24

4x+20=24

-20 -20

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4x = 4

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4 4

x= 1

7 0
3 years ago
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5 0
3 years ago
What is the completely factored form of x^4y-4x^2y-5y
AnnZ [28]

Answer:

y(x^2+1)(x^2-5)

Step-by-step explanation:

Factor the expression by first finding a GCF. Each term has the y variable and this can be pulled out as the GCF.

x^4y-4x^2y-5y\\y(x^4-4x^2-5)

To further factor the expression break the polynomial into two binomials.

To factor into two binomials, find factors that multiply to -5 and add to -4.

-5 and 1 are factors and these make the binomials (x^2+1)(x^2-5).

The final factorization is y(x^2+1)(x^2-5)

3 0
3 years ago
A fruit company delivers its fruit in two types of boxes: large and small. a delivery of 6 large boxes and 5 small boxes has a t
Afina-wow [57]
6 large + 5 small = 127 kg ------------ (1)
2 large + 3 small = 51kg    ------------ (2)

<u>(2) x 3 :</u>
6 large + 9 small = 153 ---------------- (2a)

<u>(2a) - (1) :</u>
4 small = 26
1 small = 6.5kg   ------------ (sub into equation 1)

6 large + 5 small = 127 kg
6 large + 5(6.5) = 127
6 large + 32.5 = 127
6 large = 127 - 32.5
6 large = 94.5
1 large = 15.75 kg

Answer: The small box weighs 6.5kg and the big box weighs 15.75 kg


5 0
3 years ago
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