Answer:
the dollar amount the club would have if they reached half of their goal T + 50
the dollar amount the club would have if every student at the school donated 50 cents to the cause 0,5T
the dollar amount the club could donate if they made $50 more than their goal 0.25n
the dollar amount the club would still need to raise to reach its goal after every student at the school donated 50 cents 0.5n
the dollar amount the club would have if half of the students at the school each gave 50 cents T - 0.5n
Step-by-step explanation:
the dollar amount the club would have if they reached half of their goal T + 50
the dollar amount the club would have if every student at the school donated 50 cents to the cause 0,5T
the dollar amount the club could donate if they made $50 more than their goal 0.25n
the dollar amount the club would still need to raise to reach its goal after every student at the school donated 50 cents 0.5n
the dollar amount the club would have if half of the students at the school each gave 50 cents T - 0.5n
<span>We know that OB bisects EC where they intersect would be at point O,
so the two lengths EO and OC must be equal.
2x - 20 = 70 - x
</span>[adding x + 20 to each side]
2x - 20 + x + 20 = 70 - x + x + 20
[simplifying]
<span>3x = 90
</span>[dividing each side by 3]
<span>
x = 30 would be the answer</span>
<span>h=-16t^2+24t+1
6=-16t^2+24t+1
0 = -16t^2+24t-5
0 = 16t^2-24t+5
solve the above using the "quadratic formula" which yields:
t = {0.25, 1.25}
</span>
<span><span>13</span> * (<span>12</span> - 3 <span>38</span>) = -<span>2324</span> ≅ -0.9583333</span>Calculation steps<span><span>Conversion: 3 3/8 = <span>3 · 8 + 38</span> = <span>278</span></span><span>Subtract: <span>12</span> - <span>278</span> = <span>1 · 42 · 4</span> - <span>278</span> = <span>48</span> - <span>278</span> = <span>4 - 278</span> = -<span>238</span></span><span>Multiple: <span>13</span> * (-<span>238</span>) = <span>1 · (-23)3 · 8</span> = -<span>23<span>24</span></span></span></span>
When you reflect FGH across the y-axis, you are left with the vertices of F'G'H at (2, -1) (-2, 2) (-4, -3)
The correct answer is b.
Hope this helps =)