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3 years ago

Someone PLEASE PLEASE HELP ME WITH MY QUESTION!!!

Mathematics

1 answer:

kirza4 [7]3 years ago

7 0

Use SOHCAHTOA ( this stands for sin opposite hypotenuse cos adjacent hypotenuse tan opposite adjacent)

You want the side opposite the angle and you have the hypotenuse so in this instance you would use sin...

sin (62) = x / 12

Multiply each side by 12 to get...

10.5954.... = x

To the nearest tenth it would be 10.6

Hope this helps! Any questions let me know :)

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Rewrite the point-slope equation in slope-intercept form: y - 3 = 2(x + 4)

Olin [163]

Answer:

y = 2x + 11

Step-by-step explanation:

y - 3 = 2(x + 4)

y - 3 = 2*x + 2*4

y -3 = 2x + 8

y = 2x + 8 +3

y = 2x + 11

7 0

3 years ago

Please explain how to do this,thanks

Mrrafil [7]

Well all triangles equal 180 so add up the angles you know and subtract it from 180 and you'll get the answer I think

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4 years ago

What's the equation of the line shown above?

Zigmanuir [339]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

PLEASE HELP IVE BEEN STUCK ON THIS QUESTION FOR 20 MINS IDK :(

steposvetlana [31]

Remember
$\frac{x^m}{x^n}=x^{m-n}$
and
if $a^b=a^c$ where a=a, then b=c
so
$\frac{7^9}{7^n}=7^{9-n}=7^3$
$7^{9-n}=7^3$
so
9-n=3
-n=-6
n=6

answer is 6

3 0

4 years ago

How many permutations of the 26 letters of the English alphabet do not contain any of the strings fish, rat, or bird

NARA [144]

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

$\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}$

Then

$Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\$

Note that since

$F \cap R=\varnothing$ , $Perm(F)\cap Perm(R)\ne \varnothing$

But since

$B \cap R \ne \varnothing$ , $Perm(B)\cap Perm(R)= \varnothing$

and

$B \cap F \ne \varnothing$ , $Perm(B)\cap Perm(F)= \varnothing$

Since

$|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\$

where $|Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}$

and

$|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}$

What we are looking for is the number of permutations of the 26 letters of the alphabet that do not contain the strings fish, rat or bird, or

$|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}$

This link contains another solved problem on permutations:

brainly.com/question/7951365

6 0

3 years ago