Question

Use the quadratic formula to find the solution to the quadratic equation given below. x^2-3x+9/4 =0​

Answer 1

Answer:

$x = \dfrac{3}{2}$

Step-by-step explanation:

x^2-3x+9/4 =0​

Multiply both sides by 4 to get rid of the fraction.

4x^2 - 12x + 9 = 0

$x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

$x = \dfrac{-(-12) \pm \sqrt{(-12)^2 - 4(4)(9)}}{2(4)}$

$x = \dfrac{12 \pm \sqrt{144 - 144}}{8}$

$x = \dfrac{12}{8}$

$x = \dfrac{3}{2}$