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harkovskaia [24]
3 years ago
7

Express the ratio 4:7 in the form n:1

Mathematics
2 answers:
Degger [83]3 years ago
8 0

Answer:

0.57:1

Step-by-step explanation:

Snowcat [4.5K]3 years ago
4 0

Answer:

11:1

Step-by-step explanation:

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F(n)=5.(-2)n-1<br>Complete the recursive formula of f(n).​
Alex73 [517]

Answer:

a(n) = (-2)(a_{n-1})

a_{1}=5

Step-by-step explanation:

The given expression is in the form of the explicit formula of a geometric sequence.

f(n) = a(r)^{n-1}

Where 'a' = First term of the sequence

r = common ratio

Recursive formula of a geometric sequence is,

a(n) = (a_{n-1}).(r)^{n-1}

a(n) = (-2)(a_{n-1})

Where, a_{1}=5

So the recursive formula will be a(n) = (-2)(a_{n-1})

6 0
3 years ago
Which property explains why these two expressions are equal?
ratelena [41]
Re-written, I believe the equation is:

(W+23)+5=W+(23+5)

With this, the parenthesis have nothing multiplying into it, so we can drop the parenthesis to get:

W+23+5=W+23+5
Which is the same thing.

So I'd assume it is the Associative property, because you are combining the like terms of 23 and 5.

Hope this helps!
7 0
3 years ago
(Photo) Please help me!
SOVA2 [1]
Volume =πr²*h=π*7²*4=196π
answer B
3 0
3 years ago
Analyze a graph In Exercise,analyze and sketch the graph of the function.Label any relative extrema, points of inflation,and asy
FinnZ [79.3K]

Answer:

Step-by-step explanation:

Given is a function of x

f(x) = xe^{-x}

When y=0 we get x=0 and infinity

Hence x intercept is 0 and one asymptote is x axis.

When x=0 , y =0

f'(x) = e^{-x}(-x+1)

f''(x) = e^{-x}(x-1-1)

Maxima at x=1, and point of inflection is at x=2

Increasing upto x=1 and then decreases

Graph is enclosed

6 0
3 years ago
Match the phenomenal expression on the left with the simplified version on the right
nalin [4]

Given the polynomial expression:

(y + 5)²

(y - 5)(y + 5)

Let's simplify each of the given expression:

a.) (y + 5)²

The given equation is a factor of a perfect square trinomial. For this type of expression, the following is the formula for expanding it.

\text{ (a+b)}^2\text{ = }a^2\text{ + 2ab + }b^2

We get,

\mleft(y+5\mright)^2=(y)^2+2(y)(5)+(5)^2(y+5)^2=y^2+10y+25

b.) (y - 5)(y + 5)

To be able to simplify the following expression. We will be using the formula for the difference of two squares.

(a+b)(a-b)=a^2-b^2

We get,

\mleft(y-5\mright)\mleft(y+5\mright)=(y)^2-(5)^2(y-5)(y+5)=y^2-25^{}

8 0
1 year ago
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