Answer:
2.60 moles of A remaining.
Explanation:
According to Le Chatelier's principle, the equilibrium would shift if the volume, concentration, pressure, or temperature changes.
In this question, we were told that the volume doubles, that implies that we would have to double the molarity of B/ C (since B=C.)
However, it is obvious and clear from the given equation of the reaction that A is solid in it's activity = 1. Hence, it is then ignored.
So doubling B would be 1.30 M × 2 = 2.60 M
i.e 2.60 M moles of A was consumed.
Now; the number of moles of A remaining is 5.20 - 2.60 = 2.60 moles of A remaining.
Answer:
Percent yield = 86.2%
Explanation:
Given data:
Mass of zinc = 3.68 g
Mass of zinc chloride = ?
Percent yield = ?
Actual yield = 7.12 g
Solution:
Chemical equation:
Zn + 2HCl → ZnCl₂ + H₂
Number of moles of zinc:
Number of moles = Mass /molar mass
Number of moles = 3.68 g / 65.38 g/mol
Number of moles = 0.06 mol
Now we will compare the moles of ZnCl₂ with zinc.
Zn : ZnCl₂
1 : 1
0.06 : 0.06
Theoretical yield of zinc chloride:
Mass of ZnCl₂ = moles × molar mass
Mass of ZnCl₂ = 0.06 mol × 136.286 g/mol
Mass of ZnCl₂ = 8.2 g
Percent yield:
Percent yield = actual yield / theoretical yield × 100
Percent yield = 7.12 g/ 8.2 g × 100
Percent yield = 86.2%
Answer:
The heat would flow from the hot solid to the cool solid until all temperatures are near equal.
Explanation:
It is known that the relation between heat energy, specific heat and change in temperature is as follows.
q = 
where, q = heat released or absorbed
m = mass of substance
C = specific heat
= change in temperature
It is given that mass is 25.2 g and it is added to 150 ml container so total mass will be (25.2 g + 150 g) = 175.2 g, 
is 
, 
is 
, and specific heat of water is 4.184 
.
Hence, putting the given values into the above formula as follows.
q =
= 
= 
= -8430 J
As, 1 J = 0.001 kJ. Hence, -8430 J will also be equal to -8.43 kJ. The negative sign indicates that heat is being lost.
Thus, we can conclude that heat (kJ) was lost by the solution (surroundings) is 8.43 kJ.
