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frozen [14]
3 years ago
5

The function ƒ(x) = −(x + 3)^2 − 4 is not one-to-one. Find a portion of the domain where the function is one-to-one and find an

inverse function.

Mathematics
1 answer:
Nookie1986 [14]3 years ago
3 0

Answer:

Step-by-step explanation:

The second one I believe.

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A container holds 13 quarts of water. How much is this in gallons?
patriot [66]

Answer:

3 1/4 gallons or 3.25 gallons

Step-by-step explanation:

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3 years ago
a line segment has endpoints A (-8,6) and B (4,6). What is the distance in units between point A and B?
lyudmila [28]

Answer:

The distance between point A and point B is 12 units.

Step-by-step explanation:

d = √(x2 - x1)² + (y2 - y1)²

d = √(-8 - 4)² + (6 - 6)²

d = √144 + 0

d = 12

5 0
3 years ago
(long answer needed.)
denpristay [2]

Answer:

chocolate, marshmellows, and chocolate sprinkle

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.​
Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is \dfrac{15}{2}.

To find:

The sum of first six terms.​

Solution:

We have,

S_2=6

S_4=\dfrac{15}{2}

Sum of first n terms of a GP is

S_n=\dfrac{a(1-r^n)}{1-r}              ...(i)

Putting n=2, we get

S_2=\dfrac{a(1-r^2)}{1-r}

6=\dfrac{a(1-r)(1+r)}{1-r}

6=a(1+r)                    ...(ii)

Putting n=4, we get

S_4=\dfrac{a(1-r^4)}{1-r}

\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}

\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}

\dfrac{15}{2}=6(1+r^2)            (Using (ii))

Divide both sides by 6.

\dfrac{15}{12}=(1+r^2)

\dfrac{5}{4}-1=r^2

\dfrac{5-4}{4}=r^2

\dfrac{1}{4}=r^2

Taking square root on both sides, we get

\pm \sqrt{\dfrac{1}{4}}=r

\pm \dfrac{1}{2}=r

\pm 0.5=r

Case 1: If r is positive, then using (ii) we get

6=a(1+0.5)  

6=a(1.5)  

\dfrac{6}{1.5}=a  

4=a

The sum of first 6 terms is

S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}

S_6=\dfrac{4(1-0.015625)}{0.5}

S_6=8(0.984375)

S_6=7.875

Case 2: If r is negative, then using (ii) we get

6=a(1-0.5)  

6=a(0.5)  

\dfrac{6}{0.5}=a  

12=a  

The sum of first 6 terms is

S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}

S_6=\dfrac{12(1-0.015625)}{1.5}

S_6=8(0.984375)

S_6=7.875

Therefore, the sum of the first six terms is 7.875.

5 0
3 years ago
Its a math problem Please help me !!! For the data sets below, which of the following statements is FALSE?
Evgesh-ka [11]

Answer:

fist bubble i am pretty sure

Step-by-step explanation:

7 0
2 years ago
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