The perimeter of the polygon will be given by:
Perimeter=distance around the figure
Thus the perimeter will be:
P=9.9+(9.9-5.9)+5.9+15.9+(15.9-4.6)+4.6
P=9.9+4+5.9+15.9+11.3+4.6
P=51.6
Answer: 51.6 units
Given:
In circle O, m∠R = 30.8°.
To find:
The m∠NOQ
Solution:
Central angle theorem: According to this theorem, the central angle is always twice of subtended angle on the same arc.
Angle NOQ and angle NRQ are on the same arc but ∠NOQ is the central angle and ∠NRQ is the subtended angle on the arc NQ.
Using central angle theorem, we get
![m\angle NOQ=2\times m\angle NRQ](https://tex.z-dn.net/?f=m%5Cangle%20NOQ%3D2%5Ctimes%20m%5Cangle%20NRQ)
![m\angle NOQ=2\times m\angle R](https://tex.z-dn.net/?f=m%5Cangle%20NOQ%3D2%5Ctimes%20m%5Cangle%20R)
![m\angle NOQ=2\times 30.8^\circ](https://tex.z-dn.net/?f=m%5Cangle%20NOQ%3D2%5Ctimes%2030.8%5E%5Ccirc)
![m\angle NOQ=61.6^\circ](https://tex.z-dn.net/?f=m%5Cangle%20NOQ%3D61.6%5E%5Ccirc)
Therefore,
.
Remember PEMDAS
Do parentheses, results in 25. So whats left is 87-25*(-3)+9
Then you multiply -25 by -3, answer is 75. 87+75+9
Add all of them up. 171
The answer is 171!
Answer:
22.29% probability that both of them scored above a 1520
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 1497, \sigma = 322](https://tex.z-dn.net/?f=%5Cmu%20%3D%201497%2C%20%5Csigma%20%3D%20322)
The first step to solve the question is find the probability that a student has of scoring above 1520, which is 1 subtracted by the pvalue of Z when X = 1520.
So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{1520 - 1497}{322}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B1520%20-%201497%7D%7B322%7D)
![Z = 0.07](https://tex.z-dn.net/?f=Z%20%3D%200.07)
has a pvalue of 0.5279
1 - 0.5279 = 0.4721
Each students has a 0.4721 probability of scoring above 1520.
What is the probability that both of them scored above a 1520?
Each students has a 0.4721 probability of scoring above 1520. So
![P = 0.4721*0.4721 = 0.2229](https://tex.z-dn.net/?f=P%20%3D%200.4721%2A0.4721%20%3D%200.2229)
22.29% probability that both of them scored above a 1520
Answer:
Walkway is 1.5 units²
Step-by-step explanation:
Just subtract the area of the garden from the combined area:
<u>5.5-4=1.5</u>
Also did you mean difference? I don't know what it means by sum.