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3 years ago

PLSSSS HELP fast pls !!

1 answer:

omeli [17]3 years ago

6 0

Answer:

16p^2 - 9

Step-by-step explanation:

Use FOIL method of multiplication

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saveliy_v [14]

For the numeric part, you'll have to find the GCD of 15 and 25, which is 5. So, we can factor a 5 and we have

$5(3s^{11}-5s^4)$

As for the literal part, you can factor $s^4$ because it's the power of s with the smallest denominator. So, we have

$5s^4(3s^7-5)$

8 0

2 years ago

Amiraneli [1.4K]

Answer:

Step-by-step explanation:

answer is attached below

7 0

3 years ago

LuckyWell [14K]

What I would do is subtract 12 from -5. Then you would have -17. Then you would add 4 and it would be -13. So your answer is:

8 0

3 years ago

weeeeeb [17]

The difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

<h3>How to determine the difference?</h3>

The expression is given as:

$\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$

Factor the denominators of the expressions:

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}$

Apply the difference of two squares to x² - 9

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}$

Take LCM

$\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

Hence, the difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$