The function that is graphed is y = |x -2| + 3. The correct option is D. y = |x -2| + 3
<h3>Absolute value graph</h3>
From the question, we are to determine the function for the given graph
From the graph,
When x = 2, y = 3
The equation that satisfy this condition is
y = |x -2| + 3
NOTE: This function satisfies all the points on the graph
Hence, the function that is graphed is y = |x -2| + 3
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T= total cost
n= number of days
Total cost equals the cost per day times the number of days plus the fee.
T= $39n + $65
substitute 5 for n
T= 39(5) + 65
T= 195 + 65
T= $260 total cost
Hope this helps! :)
Answer:
(2, -1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtract Property of Equality
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
2x + y = 3
-2x + 5y = -9
<u>Step 2: Solve for </u><em><u>y</u></em>
<em>Elimination</em>
- Combine equations: 6y = -6
- Divide 6 on both sides: y = -1
<u>Step 3: Solve for </u><em><u>x</u></em>
- Define equation: 2x + y = 3
- Substitute in <em>y</em>: 2x - 1 = 3
- Isolate <em>y</em> term: 2x = 4
- Isolate <em>y</em>: x = 2
<em>θ</em> is given to be in the fourth quadrant (270° < <em>θ</em> < 360°) for which sin(<em>θ</em>) < 0 and cos(<em>θ</em>) > 0. This means
cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1 ==> sin(<em>θ</em>) = -√[1 - cos²(<em>θ</em>)] = -3/5
Now recall the double angle identity for sine:
sin(2<em>θ</em>) = 2 sin(<em>θ</em>) cos(<em>θ</em>)
==> sin(2<em>θ</em>) = 2 (-3/5) (4/5) = -24/25
