WILL GIVE BRAINLIEST 10 POINTS Select all ordered pairs that satisfy the function y= -1/2x + 4

plzzzzz help me with this question . write the base and coefficient in the following terms=a.3y b. -2× c.X d. 4abc e.4(a+b f.5×

MrMuchimi

Answer:

a gas in a rigid container has a pressure of 632 torrs and a temperature of 45 celsius. The pressure has increased to 842 torrs. What is the new temperature of the gas

4 0

2 years ago

Can atriangle be formed with side lengths of 5cm. 10cm and 15cm

andreyandreev [35.5K]

Theorem of cosine:
a²=b²+c²-2bc(cos α) ⇒cos α=-(a²-b²-c²) / 2bc

In this case:
a=15 cm
b=10 cm
c=5 cm

cos α=-(15²-10²-5²) / 2*10*5
cos α=-100 / 100
cos α=-1

A=arc cos -1=180º This is impossible, because:

A+B+C=180º; then B=C=0º This is impossible for make a triangle (B>0 and C>0 if we want to make a triangle).

Therefore: it is not possible can make a triangle with side lengths of 5 cm, 10 cm and 15 cm.

3 0

3 years ago

Read 2 more answers

suppose that a water fountain produces a stream of water that follows the shape of a parabola. assigning the origin of a coordin

Readme [11.4K]

The quadratic regression equation for the stream of water is $y=-0.139x^{2} +1.667x$ {parabola}

Given that the water stream produced by fountain is parabola

Vertex of parabola is (6,5) , parbola is facing downward,axis of symmetry of parabola is x=6 and parabola passes through (0,0)

according to symmetry the third point on the parabola is (12,0)

General equation for a parabola⇒ Y=-4a $X^{2}$

⇒(y-5)=-4a $(x-6)^{2}$ { as the Vertex of parabola is (6,5) }

⇒(y-5)=-4a( $x^{2} +36-12x$ )

subtituting (0,0) in the equation to get the value of a

⇒-5=-4a(36)

⇒ a= $\frac{-5}{144}$

equation of parabola⇒(y-5)=-4( $\frac{5}{144}$ ) $(x-6)^{2}$

Therefore,The quadratic regression equation for the stream of water is $y=-0.139x^{2} +1.667x$

Learn more about parabola here:

brainly.com/question/21685473

#SPJ4

3 0

1 year ago

Solve 3x2 + 4x = −5.

Alla [95]

Move the -5 over by adding 5 to both sides
3x^2+4x+5=0
must use quadratic formula

for an equation in the form
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$

a=3
b=4
c=5

x= $\frac{-4+/- \sqrt{4^2-4(3)(5)} }{2(3)}$
x= $\frac{-4+/- \sqrt{16-60} }{6}$
x= $\frac{-4+/- \sqrt{-44} }{6}$
x= $\frac{-4+/- 2\sqrt{-11} }{6}$
remember that√-1=i
x= $\frac{-4+/- 2i\sqrt{-11} }{6}$
x= $\frac{-2+/- i\sqrt{-11} }{3}$

x= $\frac{-2+ i\sqrt{-11} }{3}$ or x= $\frac{-2- i\sqrt{-11} }{3}$

4 0

2 years ago

Your supposed to find the angle of the triangle but I know the answer 145 but I want to know how you get the answer

Inga [223]

A straight line adds up to 180
So the line opposite of 137 should add up to 180
This gives us the equation 137+x=180 then x=43

The triangle also adds up to 180 degrees
So 102+43+x=180
The equation can be simplified to 145+x=180 therefore x=35

So x+?=180 because it is a straight line.
We can substitute x in making the equation 35+?=180
Now we want to solve for the ? so we'll subtract 35 from each side
This leaves us with the equation ?=145

So we now know that the ?=145

4 0

3 years ago