Find the product<br> -5. 12 =

What is reciprocal of the fraction in the equation 3/5(2x+8)=18?

Katen [24]

Answer:

5/3

Step-by-step explanation:

The reciprocal is the fraction upside down.

3 0

2 years ago

Which of the following states the conditions that the graph meets?

Sladkaya [172]

B is correct
I just took it

8 0

2 years ago

A model giraffe has a scale of 1 in : 3 ft. If the model giraffe is 4 in tall, then how tall is the real giraffe

VladimirAG [237]

The answer is 12ft. Because if 1in is 3ft then 4in will be 4 multiplied by 3

4 0

3 years ago

Read 2 more answers

The product of two irrational numbers is. Rational

Snowcat [4.5K]

Answer:

So the statement:

"The product of two irrational numbers is rational." is false.

Step-by-step explanation:

The product of two irrationals can be irrational or rational.

Example:

$\sqrt{2} \cdot \sqrt{2}=2$

$\sqrt{2}$ is irrational but when you multiply it to itself the output is rational.

Example:

$\sqrt{2} \cdot \sqrt{3}=\sqrt{6}$

$\sqrt{2} \text{ and } \sqrt{3}$ are irrational and when you multiply them you get an irrational answer of $\sqrt{6}$ .

So the statement:

"The product of two irrational numbers is rational." is false.

5 0

2 years ago

(5) Find the Laplace transform of the following time functions: (a) f(t) = 20.5 + 10t + t 2 + δ(t), where δ(t) is the unit impul

Aloiza [94]

Answer

(a) $F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}$

(b) $F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}$

Step-by-step explanation:

(a) $f(t) = 20.5 + 10t + t^2 +$ δ(t)

where δ(t) = unit impulse function

The Laplace transform of function f(t) is given as:

$F(s) = \int\limits^a_0 f(s)e^{-st} \, dt$

where a = ∞

=> $F(s) = \int\limits^a_0 {(20.5 + 10t + t^2 + d(t))e^{-st} \, dt$

where d(t) = δ(t)

=> $F(s) = \int\limits^a_0 {(20.5e^{-st} + 10te^{-st} + t^2e^{-st} + d(t)e^{-st}) \, dt$

Integrating, we have:

=> $F(s) = (20.5\frac{e^{-st}}{s} - 10\frac{(t + 1)e^{-st}}{s^2} - \frac{(st(st + 2) + 2)e^{-st}}{s^3} )\left \{ {{a} \atop {0}} \right.$

Inputting the boundary conditions t = a = ∞, t = 0:

$F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}$

(b) $f(t) = e^{-t} + 4e^{-4t} + te^{-3t}$

The Laplace transform of function f(t) is given as:

$F(s) = \int\limits^a_0 (e^{-t} + 4e^{-4t} + te^{-3t} )e^{-st} \, dt$

$F(s) = \int\limits^a_0 (e^{-t}e^{-st} + 4e^{-4t}e^{-st} + te^{-3t}e^{-st} ) \, dt$

$F(s) = \int\limits^a_0 (e^{-t(1 + s)} + 4e^{-t(4 + s)} + te^{-t(3 + s)} ) \, dt$

Integrating, we have:

$F(s) = [\frac{-e^{-(s + 1)t}} {s + 1} - \frac{4e^{-(s + 4)}}{s + 4} - \frac{(3(s + 1)t + 1)e^{-3(s + 1)t})}{9(s + 1)^2}] \left \{ {{a} \atop {0}} \right.$

Inputting the boundary condition, t = a = ∞, t = 0:

$F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}$

3 0

3 years ago

Find the product -5. 12 =