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3 years ago

Find the product -5. 12 =

Mathematics

1 answer:

KatRina [158]3 years ago

7 0

The product of -5 and 12 is -60

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At a basketball game, 95% of people attending were supporting the home team, while 5% were supporting the visiting team. If 532

Serggg [28]

Answer:

559

Step-by-step explanation:

532*.05

26.6

aout 27 people attended the other team's game

532+27 = 559

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2 years ago

What is the volume of a pentagonal prism that has a base area of 5.16 cm2 and a height of 9 cm? 46.44 cm 3 19.32 cm 3 55.32 cm 3

Zanzabum

Answer:

16.44 would be your right answer

Step-by-step explanation:

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2 years ago

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Calculate the area of kite PQRS.

Sonbull [250]

Check the picture below

so, just get the area of each triangle, and sum them up, that's the area of the kite

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2 years ago

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Help solve<br> 34 = 28 - 2/5X

NARA [144]

34 = 28 - 2/5X

Move +28 to the other side. Sign changes from +28 to -28

34-28=28-28-2/5x

34-28=-2/5x

6=-2/5x

Multiply both sides by -5/2

6(-5/2)=-2/5(-5/2)x

Cross out 6 and 2, divide by 2 and becomes :

3*-5=-15=X

Answer: X=-15

3 0

2 years ago

Zadanie optymalizacyjne z matematyki. Proszę o rozwiązanie i wyjaśnienie

Yakvenalex [24]

Volume of the pyramid:

$V=\dfrac{s^2h}3$

Perimeter of the cross-section:

$40=\sqrt2\,s+2\sqrt{\dfrac{s^2}2+h^2}=\sqrt2\left(s+\sqrt{s^2+2h^2}\right)$

$\implies h=\sqrt{\dfrac{(20\sqrt2-s)^2-s^2}2}=\sqrt{400-20\sqrt2\,s}$

Area of the cross-section:

$P=\dfrac12(\sqrt2\,s)h=\dfrac{sh}{\sqrt2}$

$\implies P=\dfrac{s\sqrt{400-20\sqrt2\,s}}{\sqrt2}=s\sqrt{200-10\sqrt2\,s}$

First derivative test:

$\dfrac{\mathrm dP}{\mathrm ds}=\dfrac{20\sqrt2-3s}{\sqrt{4-\dfrac{\sqrt2}5s}}=0\implies s=\dfrac{20\sqrt2}3$

Then the height of the cross-section/pyramid is

$h=\sqrt{400-20\sqrt2\,s}=\dfrac{20}{\sqrt3}$

The volume of the pyramid that maximizes the cross-sectional area $P$ is

$V=\dfrac{\left(\frac{20\sqrt2}3\right)^2\frac{20}{\sqrt3}}3=\dfrac{16000}{27\sqrt3}$

5 0

2 years ago