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Anni [7]
3 years ago
7

Find the product -5. 12 =

Mathematics
1 answer:
KatRina [158]3 years ago
7 0
The product of -5 and 12 is -60
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1.94x - 10/8x + 4.32 = [2(1.15x+8.5)]
kipiarov [429]
1,94x-\frac{10}{8}x+4,32=[2(1,15x+8,5)]\\\\
1,94x-1,25x+4,32=2,3x+17\\\\
0,69x+4,32=2,3x+17\ \ \ |Subtract\ 2,3x\\\\
-1,61x+4,32=17\ \ \ |Subtract\ 4,32\\\\
-1,61x=12,68\ \ \ |Divide\ by\ -1,61\\\\\boxed{x\approx7,9}

8 0
3 years ago
How do I solve p(q-2)(r-3)
guajiro [1.7K]
Since you have parentheses, you will first multiply (q-2)*(r-3) which equals (qr+6). So now its simplified to p(qr+6) which equals pqr+p6.
5 0
3 years ago
Square root 1.96? is rational irrational
Kruka [31]

Answer:

Rational

Step-by-step explanation:

An irrational number is a number with forever continuing decimals. Plug it into the calc and you can see if there is a long decimal line that ends. You should get 1.4 in the calc, and since it does end, it is a rational number.

4 0
3 years ago
What is the answer to this problem? 3(2x-5)-4x+8=-2x+1
Troyanec [42]

Answer:

Step-by-step explanation:

4 0
3 years ago
Three times each day, a quality engineer samples a component from a recently manufactured batch and tests it. Each part is class
Tresset [83]

Answer:

Step-by-step explanation:

Hello!

Three samples of components manufactured are taken per day. They are classified as:

D: "Conforming (suitable for its use)"

E: "Downgraded (unsuitable for the intended purpose but usable for another purpose)"

F: "Scrap (not usable)"

This classification includes the three events that may occur in your sample space S. The experiment consists in recording the categories of the three parts tested in a day.

a. List the 27 outcomes in the sample space.

The possible outcomes in the space sample are the combinations of the three events. To avoid using the same letters as in the following questions I've named the evets as D, E, and F

S={DDD, DED, DFD, DEF, DFE, DEE, DFF, DDE, DDF , EDE, EEE, EFE, EED, EEF, EDF, EFD, EDD, EFF , FDF, FEF, FFF, FFE, FFD, FDE, FED, FDD, FEE}

b. Let A be the event that all the parts fall into the same category. List the outcomes in A.

A: "All the parts fall into the same category"

You have three possible outcomes for this event, that the three compounds are conforming, "DDD", that the three are unconforming, "EEE", or that the three compounds are scrap, "FFF". There are only three possible outcomes for this event.

S={DDD, EEE, FFF}

c. Let B be the event that there is one part in each category. List the outcomes in B.

B: "There is a part in each category"

This means, for example, The first one is conforming "D", the second one is unconforming "E" and the third one is scrap "F", then the first one may be unconforming "E", the second one is conforming "D" and the thirds one is scrap "F", and so on, you have 6 possible outcomes for this event:

S={DEF, DFE, EDF, EFD, FDE, FED}

d. Let C be the event that at least two parts are conforming. List the outcomes in C.

C: "At least two parts are conforming"

For this event, you can have two of the compounds to be considered conforming or the three of them.

S={DDD, DED, DFD, DDE, DDF , EDD, FDD}

A total of 7 combinations fit this event.

I hope you have a SUPER day!

6 0
3 years ago
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