What is the y-intercept of the following equation. 3x-2y=6

1 answer:

7 0

3x-2y=6

1) Add -3x to both sides.
 3x−2y=6
+3x +3x
-----------------
−2y=−3x+6

2) Divide both sides by -2.
 $\frac{-2y}{-2}$ = $\frac{−3x+6}{-2}$

y=32x−3

3) Substitute the y with the equation
3x-2(32x-3)=6
3x-64x+6=6

4) Combine like terms
3x-64x+6=6
-61x+6=6

5) Subtract 6 from each side of the equation
-61x+6=6
-6 -6 (+6-5 gets crossed out)
--------------
-61x=0

6) Divide both sides by -61
$\frac{-61x}{-61} = \frac{0}{-61}$
x=0

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Now that you've got you x intercept, use the x value and substitute it into the
y=32x−3

y=32(0)-3
y=0-3
y=-3

(0,-3)

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For the function f(x)=x2−24÷3+12 f(1) f(0) f(−1)

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Put the values of x to the equation of the function.

$f(x)=\dfrac{x^2-24}{3}+12$

$f(1)=\dfrac{1^2-24}{3}+12=\dfrac{1-24}{3}+12=\dfrac{-23}{3}+12=-7\dfrac{2}{3}+12=4\dfrac{1}{3}\\\\f(0)=\dfrac{0^2-24}{3}+12=\dfrac{-24}{3}+12=-8+12=4\\\\f(-1)=\dfrac{(-1)^2-24}{3}+12=\dfrac{1-24}{3}+12=\dfrac{-23}{3}+12=-7\dfrac{2}{3}+12=4\dfrac{1}{3}$