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mamaluj [8]
3 years ago
13

What is the y-intercept of the following equation. 3x-2y=6

Mathematics
1 answer:
tester [92]3 years ago
7 0
3x-2y=6

1) <span>Add -3x to both sides.
</span><span><span>  3x</span>−<span>2y</span></span>=<span>6
</span>+3x      +3x
-----------------
<span>−<span>2y</span></span>=<span><span>−<span>3x</span></span>+<span>6
</span></span><span>
2) Divide both sides by -2.
</span>\frac{-2y}{-2} = \frac{−3x+6}{-2}

y=<span><span><span>32</span>x</span>−<span>3
</span></span>
3) Substitute the y with the equation
3x-2(32x-3)=6
3x-64x+6=6

4) Combine like terms
3x-64x+6=6
-61x+6=6

5) Subtract 6 from each side of the equation
-61x+6=6
        -6 -6        (+6-5 gets crossed out)
--------------
-61x=0

6) Divide both sides by -61
\frac{-61x}{-61} =  \frac{0}{-61} 
x=0

============================================================

Now that you've got you x intercept, use the x value and substitute it into the
y=32x−3

y=32(0)-3
y=0-3
y=-3

(0,-3)
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