4 2/3+5x=7-2x
Add 2x to both sides.
4 2/3+7x=7
Subtract 4 2/3 on both sides.
7x=2 1/3
7x=7/3
Divide by 7 on both sides.
x=1/3
answer: x=1/3
Answer:
(a) The probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b) The probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Step-by-step explanation:
Let the random variable <em>X</em> follow a Normal distribution with parameters <em>μ</em> = 155.4 and <em>σ</em> = 49.5.
(a)
Compute the probability that a single randomly selected value lies between 158.6 and 159.2 as follows:

*Use a standard normal table.
Thus, the probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b)
A sample of <em>n</em> = 246 is selected.
Compute the probability that a sample mean is between 158.6 and 159.2 as follows:

*Use a standard normal table.
Thus, the probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Answer:
7
Step-by-step explanation:
Count the numbers in between (0,0) and (0,7).
Answer:
the first one
Step-by-step explanation:
yellow line is an exponential graph
blue line is a log graph
the purple in the middle is a sort of "combo" of the two