I: y=(1/2)x+5
II: y=(-3/2)x-7
substitution:
fancy word for insert the definition of one variable in one equation into the other
-> isolate a variable, luckily y is isolated (even in both equations) already
-> substitute y of II into I (=copy right side of II and replace y in I with it):
(-3/2)x-7=(1/2)x+5
-3x-14=x+10
-3x-24=x
-24=4x
-6=x
-> insert x back into I (or II):
y=(1/2)x+5
=(1/2)*(-6)+5
=-3+5=2
elimination: subtract one equation from the other to eliminate a variable, again y is already isolated->no extra work required
I-II:
y-y=(1/2)x+5-[(-3/2)x-7]
0=(1/2)x+5+(3/2)x+7
0=(4/2)x+12
-12=2x
-6=x
-> insert x back into I (or II):
y=(1/2)x+5
=(1/2)*(-6)+5
=-3+5=2
Answer:
x-0,6x=20
0,4x=20/:0,4
x=50
Step-by-step explanation:
Wouldn't it be 81?
Because 9x9=81
And that's how you get perfect squares
Step-by-step explanation:
h varies directly with a and inversely with b.
2 is the constant of variation.
For this case we have a function of the form:
Where,
A: initial population of rabbits
b: growth rate
x: time in months
Substituting values we have:
For the month number 12 we have:
Rounding to the nearest whole number we have:
Answer:
For month number 12, the approximate population of rabbits is:
