Answer:
I think it should be 5y+24
Answer:
Step-by-step explanation:
Given that :
Mean = 7.8
Standard deviation = 0.5
sample size = 30
Sample mean = 7.3 5.4772
The null and the alternative hypothesis is as follows;
The test statistics can be computed as :
The p-value at 0.05 significance level is:
p-value = 1- P( Z < -5.4772)
p value = 0.00001
Decision Rule:
The decision rule is to reject the null hypothesis if p value is less than 0.05
Conclusion:
At the 0.05 significance level, there is sufficient information to reject the null hypothesis. Therefore ,we conclude that college students watch fewer movies a month than high school students.
Answer:
-6 > 12
Step-by-step explanation:
boom roasted. and I need to right more ig
<span>For the
presented problem, the solution would be</span><span> </span><span>v</span><span>(0)=0</span><span>v(0)=0</span><span> is</span><span>v</span><span>(</span><span>t</span><span>)−</span><span>mgb</span><span>=</span><span>e</span><span>−</span><span>b</span><span>/</span><span>m</span><span>⋅</span><span>t</span><span>(</span><span>v</span><span>0</span><span>−</span><span>mgb</span><span>)</span><span>⟺</span><span>v</span><span>(</span><span>t</span><span>)=</span><span>mgb</span><span>(</span><span>1−</span><span>e</span><span>−</span><span>b</span><span>/</span><span>m</span><span>⋅</span><span>t</span><span>)</span><span>≈</span><span>g</span><span>⋅</span><span>t</span><span>−</span><span>gb</span><span>2</span><span>m</span><span>⋅</span><span>t</span><span>2</span><span>,
with the following given, </span><span>
m</span><span>=180[lb]=81.6[kg]</span><span> </span>
<span>g</span><span>=9.81[m/s</span><span>2</span><span>]</span><span />
<span>b</span><span>=0.75[kg</span><span>⋅</span><span>m/s</span><span>2</span><span>⋅</span><span>s/ft]=0.2286[kg/s]</span><span />
<span>The solution that the
friction provides is </span><span>v</span><span>(</span><span>t</span><span>)=3501.7[m/s]</span><span>⋅</span><span>(</span><span>1−</span><span>e</span><span>−0.00280[1/s]</span><span>⋅</span><span>t</span><span>), where I get </span><span><span>96.69</span></span><span /><span><span><span><span>[</span></span><span /><span><span>m</span></span><span /><span><span><span><span>/</span></span></span></span></span><span><span><span>s</span></span><span /><span><span>]</span></span></span><span>=</span></span><span /><span><span>317.2</span></span><span /><span><span><span><span>[</span></span><span /><span><span>f</span><span>t</span></span><span /><span><span><span><span>/</span></span></span></span></span><span><span><span>s</span></span><span /><span><span>]</span></span></span></span><span><span /></span><span>. I
am hoping that this answer has satisfied your query about this specific
question.<span /></span>
Answer:
No, because both of them will never be able to match; become equivalent. You would have to multiply 2 different numbers to make them match, meaning they would not be proportional. For a comparison to be proportional, the ratio you are trying to simplify to must be achieved by multiplying 2 numbers from the previous ratio by one LCD.
They are<em> able</em> to make 12/21, but that does not mean they are proportional.
