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Anna11 [10]
3 years ago
9

Given that x is an integer, what is the solution of |x-1|

a1" title=" \leqslant 1" alt=" \leqslant 1" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
5 0

Answer:

see explanation

Step-by-step explanation:

Inequalities of the type | x | ≤ a always have solutions of the form

- a ≤ x ≤ a

Given

| x - 1 | ≤ 1 then

- 1 ≤ x - 1 ≤ 1 ( add 1 to each of the 3 intervals )

0 ≤ x ≤ 2

Since we require an integer solution then x = 0, 1, 2

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A cab charges the following fare for each trip.
Sphinxa [80]

Answer:

32.25

Step-by-step explanation:

6 0
3 years ago
A sanitation department is interested in estimating the mean amount of garbage per bin for all bins in the city. In a random sam
soldi70 [24.7K]

Answer:

a) 52.8-2.02\frac{3.9}{\sqrt{40}}=51.554    

b) 52.8+2.02\frac{3.9}{\sqrt{40}}=54.046    

c) 52.8-2.71\frac{3.9}{\sqrt{40}}=51.129  

d) 52.8+2.71\frac{3.9}{\sqrt{40}}=54.471  

e) Yes, depends of the confidence level.

At 95 % of confidence the value 54.1985 pounds is not included on the interval. At 5% of significance the statement is FALSE.

At 99 % of confidence the value 54.1985 pounds is included on the interval. So at 1% of significance the statement is TRUE.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X =52.8 represent the sample mean for the sample

\mu population mean (variable of interest)

s=3.9 represent the sample standard deviation

n=40 represent the sample size  

a) What is the lower limit of the 95% interval? Give your answer to three decimal places

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=40-1=39

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,39)".And we see that t_{\alpha/2}=2.02

Now we have everything in order to replace into formula (1):

52.8-2.02\frac{3.9}{\sqrt{40}}=51.554    

b) What is the upper limit of the 95% interval? Give your answer to three decimal places

52.8+2.02\frac{3.9}{\sqrt{40}}=54.046    

So on this case the 95% confidence interval would be given by (51.554;54.046)    

c) What is the lower limit of the 99% interval? Give your answer to three decimal places

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,39)".And we see that t_{\alpha/2}=2.71

Now we have everything in order to replace into formula (1):

52.8-2.71\frac{3.9}{\sqrt{40}}=51.129  

d) What is the upper limit of the 99% interval? Give your answer to three decimal places

52.8+2.71\frac{3.9}{\sqrt{40}}=54.471  

So on this case the 99% confidence interval would be given by (51.129;54.471)    

e) Consider the claim that the mean amount of garbage per bin is 54.1985 pounds. Is the following statement true or false? The decision about the claim would depend on whether we use a 95% or 99% confidence interval: True/False

Yes, depends of the confidence level.

At 95 % of confidence the value 54.1985 pounds is not included on the interval. At 5% of significance the statement is FALSE.

At 99 % of confidence the value 54.1985 pounds is included on the interval. So at 1% of significance the statement is TRUE.

3 0
4 years ago
Best one gets brainly :D
Inessa05 [86]

Answer:

The first and the second equation is flipped... meaning you have to switch their places

Step-by-step explanation:

I think I did this before so good luck...

4 0
3 years ago
The following function is probability Distribution function.
Rina8888 [55]

Answer:

9.60 ; - 60.96

Step-by-step explanation:

Given the function :

F(x)=6(x+1) /25, x=0, 1, 2, 3, 4.

x = 0

F(0)=6(0+1)/25 = 6/25 = 0.24

x = 1

F(1)=6(1+1)/25 = 12/25 = 0.48

x = 2

F(2)=6(2+1)/25 = 18/25 = 0.72

x = 3

F(2)=6(3+1)/25 = 24/25 = 0.96

x = 4

F(2)=6(4+1)/25 = 30/25 = 1.2

X ______0 _____ 1 ______ 2 ______ 3 ____ 4

P(x) ___ 0.24 __ 0.48 ___ 0.72 ____ 0.96 __ 1.2

Mean, μ = Σx*p(x) :

(0*0.24) + (1*0.48) + (2*0.72) + (3*0.96) + (4*1.2)

= 9.60

Variance : Σx²*p(x) - μ²

(0^2*0.24) + (1^2*0.48) + (2^2*0.72) + (3^2*0.96) + (4^2*1.2) - 9.6^2

= 31.2 - 92.16

= - 60.96

4 0
3 years ago
What is the value of the fourth power of ten
krok68 [10]
I think it 4194304 i THINK thats the answer

7 0
3 years ago
Read 2 more answers
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