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3 years ago

What Group would this element be in?

Chemistry

1 answer:

AleksandrR [38]3 years ago

8 0

Answer:

Non-metals because it has 9 electrons meaning it is fluorine

Explanation:

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Scientists classify organisms into three domains and six kingdoms. In which

SIZIF [17.4K]

Answer:

c is correct option

according to the question.

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3 years ago

What are valency and radicals

PolarNik [594]

Valency- it means the combing capacity if an element.
<span> radical- it is an atom, molecule, or ion that has unpaired valence electrons or an open electron shell.
</span>

6 0

3 years ago

A stock solution is 28.2 percent ammonia (NH3) by mass, and the solution has a density of 0.8990 grams per milliliter. What volu

Savatey [412]

Answer:

$\boxed{\text{20.2 mL}}$

Explanation:

Assume that the volume of the stock solution is 1 L.

1. Mass of stock solution

$\text{Mass} = \text{1000 mL} \times \dfrac{\text{0.8990 g}}{\text{1 mL}} = \text{899.0 g}$

2.Mass of NH₃

$\text{Mass of NH}_{3} = \text{899.0 g stock} \times \dfrac{\text{28.2 g NH}_{3}}{\text{100 g stock}} = \text{253.5 g NH}_{3}$

3. Moles of NH₃

$\text{Moles of NH}_{3} = \text{253.5 g NH}_{3}\times \dfrac{\text{1 mol NH}_{3}}{\text{17.03 g NH}_{3}}= \text{14.89 mol NH}_{3}$

4. Molar concentration of stock solution

$c = \dfrac{\text{moles}}{\text{litres}} = \dfrac{\text{14.89 mol}}{\text{1 L}} = \text{14.89 mol/L}$

5. Volume of stock needed for dilution

Now that you know the concentration of the stock solution, you can use the dilution formula .

$c_{1}V_{1} = c_{2}V_{2}$

to calculate the volume of stock solution.

Data:

c₁ = 14.89 mol·L⁻¹; V₁ = ?

c₂ = 0.500 mol·L⁻¹; V₂ = 600 mL

Calculations:

$\begin{array}{rcl}14.89V_{1} & = & 0.500 \times 600\\14.89V_{1} & = & 300\\V_{1} & = & \text{20.2 mL}\\\end{array}\\\text{You will need $\boxed{\textbf{20.2 mL}}$ of the stock solution.}$

4 0

3 years ago

If 10.0g of powdered iron is heated with 10.0g of sulfur in an open crucible, what is the mass of iron (II) sulfide that is form

Ugo [173]

Answer:

See Explanation

Explanation:

8Fe + S₈ => 8FeS

Given: 10g 10g

moles 10g/56g/mol 10g/256g/mol

= 0.179mol Fe = 0.039mol S₈

Reduce => divide mole values by respective coefficients; smaller value is Limiting Reactant.

0.179/8 = 0.022 0.039/1 = 0.039

=> Fe is limiting reactant

8Fe + S₈ => 8FeS

Given: 10g/56g/mol 10g/256g/mol

= 0.179mol = 0.039 mol 0.179mol FeS produced

1/8(0.179)mol S₈ used (coefficients are equal,

= 0.022 mol S₈ used => moles Fe = moles FeS)

= (0.039 - 0.022)mol S₈ = 0.179mol FeS

remains in excess =(0.179mol)(88g/mol)

= 0.0166 mol S₈ (excess) = 15.8 g FeS

= (0.0166mol)(256g/mol) (Theoretical Yield)

= 4.26g S₈ in excess

7 0

3 years ago

The process by which a solid changes to a liquid is

Mumz [18]

a process called melting.

6 0

4 years ago

Read 2 more answers