Question

6) A 14.5 g sample of sodium chloride reacts with excess fluorine gas according to

Answer 1

The mass of  chlorine gas produced by 14.5 grams of sodium chloride is 10.42 g.

The mass of  chlorine gas produced by 14.5 grams of sodium chloride is 8.81 g.

The given parameters;

• mass of the sodium chloride, = 14.5 g
• 2NaCl(s) + F2(g) → 2NaF(s) + Cl2(g)

In the reaction above, we can deduce the following;

molecular mass of 2Nacl = 2(58.44) = 116.88 g

molecular mass of 2NaF = 2(42) = 84 g

molecular mass of  Cl2 = 71 g

The mass of sodium fluoride produced by 14.5 grams of sodium chloride is calculated as follows;

116.88 g of NaCl --------------- 84 g of NaF

14.5 g of NaCl -------------------  ?

$= \frac{84 \times 14.5}{116.88} \\\\= 10.42 \ g$

The mass of  chlorine gas produced by 14.5 grams of sodium chloride is calculated as follows;

116.88 g of NaCl --------------- 71 g of Cl2

14.5 g of NaCl ------------------- ?

$= \frac{14.5 \times 71}{116.88} \\\\= 8.81 \ g$

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