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egoroff_w [7]
3 years ago
14

6) A 14.5 g sample of sodium chloride reacts with excess fluorine gas according to

Chemistry
1 answer:
Ann [662]3 years ago
8 0

The mass of  chlorine gas produced by 14.5 grams of sodium chloride is 10.42 g.

The mass of  chlorine gas produced by 14.5 grams of sodium chloride is 8.81 g.

The given parameters;

  • <em>mass of the sodium chloride, = 14.5 g</em>
  • <em>2NaCl(s) + F2(g) → 2NaF(s) + Cl2(g)</em>

<em />

In the reaction above, we can deduce the following;

molecular mass of 2Nacl = 2(58.44) = 116.88 g

molecular mass of 2NaF = 2(42) = 84 g

molecular mass of  Cl2 = 71 g

The mass of sodium fluoride produced by 14.5 grams of sodium chloride is calculated as follows;

116.88 g of NaCl --------------- 84 g of NaF

14.5 g of NaCl -------------------  ?

= \frac{84 \times 14.5}{116.88} \\\\= 10.42 \ g

The mass of  chlorine gas produced by 14.5 grams of sodium chloride is calculated as follows;

116.88 g of NaCl --------------- 71 g of Cl2

14.5 g of NaCl ------------------- ?

= \frac{14.5 \times 71}{116.88} \\\\= 8.81 \ g

Learn more here:brainly.com/question/8470145

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Answer:

7.12 mm

Explanation:

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F = kqq'/r².................... Equation 1

Where F = force, k = proportionality constant, q and q' = The two point charges, r = distance between the two charges.

Make r the subject of the equation,

r = √(kqq'/F).......................... Equation 2

Given: q = q' = 75.0 nC = 75×10⁻⁹ C, F = 1.00 N

Constant: k = 9.0×10⁹ Nm²/C².

Substitute into equation 2

r = √[ (75×10⁻⁹ )²9.0×10⁹/1]

r = 75×10⁻⁹.√(9.0×10⁹)

r = (75×10⁻⁹)(9.49×10⁴)

r = 711.75×10⁻⁵

r = 7.12×10⁻³ m

r = 7.12 mm

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3 years ago
Place the following in order of increasing acid strength. HBrO2 HBrO3 HBrO HBrO4 A) HBrO2
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Answer:

HBrO4 < HBrO3 < HBrO2 < HBrO

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Consider an ideal gas enclosed in a 1.00 L container at an internal pressure of 14.0 atm. Calculate the work, w , if the gas exp
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If the dehydration reaction of an alcohol is successful. What changes would be seen in the ir spectrum for the product compared
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If the dehydration reaction of an alcohol is successful. The changes would be seen in the IR spectrum for the product compared to the starting material are as,

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In dehydration reaction of alcohol (  O-H and  C-O bond ) contain , the water molecule ( H_{2}O ) is release from the reactant and C-C double bond is form which is known as alkene in the product .

The reactant and product have different structure. To determine the structure of the compound IR spectroscopy is used. In IR spectrum the peak corresponds to 3400-3600 cm is missing in the product of  dehydration reaction of an alcohol. It means  O-H band is disappear from stating material.

learn about IR SPECTRUM

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4 0
2 years ago
A hiker has packed a bag of chips as a snack. At the start of the hike the pressure was 1.5 atm and the temperature was 35*C. At
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According to <span>Gay-Lussac's Law the temperature and Pressure are directly proportional to each other if the amount and volume of given gas are kept constant.
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                                          P</span>₁ / T₁  =  P₂ / T₂     ----- (1)
Data Given;
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Solving Eq. 1 for P₂,

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Putting values,
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Result:
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