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mariarad [96]
3 years ago
8

Environment is not ___ uniform all form​

Mathematics
2 answers:
zhenek [66]3 years ago
8 0

environment is not natural uniform all from

RUDIKE [14]3 years ago
8 0

Answer:

<h2>Natural</h2>

Step-by-step explanation:

<h3>Environment is not <em><u>natural</u></em> uniform all form.</h3>

Hope it is helpful to you ☺️

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Hi how do I solve this? Step by step please
Gekata [30.6K]

Answer:

break it down by using pmedas

7 0
3 years ago
(1 point) let a=⟨−4,−3,2⟩a=⟨−4,−3,2⟩. find a unit vector in the same direction as aa.
sergij07 [2.7K]
A unit vector in the direction of a would be the vector a multiplied by a factor such that the length of vector a is unity.
The magnitude of a is given by:
|a|
=sqrt(4^2+3^2+2^2)   [ I got lazy instead of writing (-4)^2+(-3)^2+2^2]
=sqrt(29).

So the univector is a/sqrt(29), or (-4/sqrt(29),-3/sqrt(29), 2/sqrt(29), or simply (-4,-3,2)/sqrt(29).

8 0
3 years ago
7. (3 pt) What is the distance between points (−2, 8) and (6, −2)? Round to the nearest tenth of a unit.
inysia [295]
The Exact answer is 12.80625, Rounded to the tenth is 12.8
8 0
3 years ago
Meiko is hanging a picture collage on her wall. The dimensions of the collage are shown in the diagram. She plans to cover
alexira [117]

Answer: \frac{A_{collage}}{15.75\ in^2}

Step-by-step explanation:

Since you did not attach the diagram and I don't know the dimensions of the collage, I will give you a general explanation of the procedure you need to use in order to solve the exercise:

1. You need to use the formula for calculate the area of a rectangle:

A=lw

Where "l" is the length and "w" is the width.

2. Using the formula, you must calculate the area of an small picture.

You know that its length is 4.5 inches and its width is 3.5 inches. Therefore, its area is:

A_{picture}=(4.5\ in)(3.5\ in)\\\\A_{picture}=15.75\ in^2

3. Calculate the area of the collage using the formula:

A_{collage}=(l_{collage})(w_{collage})

4. Finally, divide the area of the collage by the area of an small picture in order to find the number of small pictures that will fit within the collage:

\frac{A_{collage}}{15.75\ in^2}

5 0
3 years ago
Read 2 more answers
Can anyone help me? I'll give 20 points
Airida [17]

Answer:

Top answer · 0 votes

Q = 1.6LH3/2 38.4 = 1.6(3)(H3/2) H3/2 = 38.4/4.8 H3/2 = 8 (H3/2)2/3 = 82/3 Note that 82/3 = (3√8)2 = 22 = 4 The height is 4 ft  

Step-by-step explanation:

6 0
3 years ago
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