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VashaNatasha [74]
2 years ago
14

Consider the following diagram of a chemical reaction.

Chemistry
2 answers:
kirill [66]2 years ago
6 0

Answer:

The answer is A

Explanation:

on EDG 2021

USPshnik [31]2 years ago
5 0

Answer: a polymer

Explanation:

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What is the correct formula for Heptarsenic Tetrabromide
harina [27]
Hepta is seven and tetra is four, so option c is your answer
3 0
3 years ago
What is the percent yield of 20.0g P4 O10 are produced?
enyata [817]

Answer:

You must divide the grams of your actual yield by the grams of the theoretical yield and multiply by 100 in order to obtain percent yield

Explanation:

7 0
3 years ago
What are the prompt neutrons that occur during nuclear fission?
zysi [14]

Answer:

Prompt Neutrons

Explanation:

Principle. Using uranium-235 as an example, this nucleus absorbs thermal neutrons, and the immediate mass products of a fission event are two large fission fragments, which are remnants of the formed uranium-236 nucleus. These fragments emit two or three free neutrons (2.5 on average), called prompt neutrons.

4 0
3 years ago
When reactants and products are being formed at an equal rate in a chemical reaction, the ____. a. reaction is endergonic b. fre
attashe74 [19]
<h2>The answer is option b "free energy is zero"</h2>

Explanation

  • The reaction that has negative free energy are called exergonic reactions that means the reactants have more free energy than the product formed.
  • The reaction that has positive free energy are called endergonic reactions that means the final state or the products formed have more free energy than the initial state or the reactants.
  • The reaction that has zero free energy occurs when the free energy of both reactants and the products are same hence the rate of formation of products and reactants are equal.
  • Therefore, when reactants and products are being formed at an equal rate the free energy is zero.
3 0
3 years ago
Given the unbalanced equation below, answer the following: Calculate the number of liters of 3.00 M lead (II) iodide solution pr
mr_godi [17]

The number of liters of 3.00 M lead (II) iodide : 0.277 L

<h3>Further explanation</h3>

Reaction(balanced)

Pb(NO₃)₂(aq) + 2KI(aq) → 2KNO₃(aq) + PbI₂(s)

moles of KI = 1.66

From the equation, mol ratio of KI : PbI₂ = 2 : 1, so mol PbI₂ :

\tt \dfrac{1}{2}\times 1.66=0.83

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large \boxed {\bold {M ~ = ~ \dfrac {n} {V}}}

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

So the number of liters(V) of 3.00 M lead (II) iodide-PbI₂ (n=0.83, M=3):

\tt V=\dfrac{n}{M}\\\\V=\dfrac{0.83}{3}\\\\V=0.277~L

5 0
3 years ago
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